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xerj
January 28th 07, 10:54 PM
I remember that sin c = excess thrust/weight

What step do I then do to convert sin c into degrees above the horizon?

TIA

Tony
January 28th 07, 11:21 PM
You simply want to know what angle has that sine. arc sin (c) would be
the function on the calculator you're looking for.
On Jan 28, 5:54 pm, "xerj" > wrote:
> I remember that sin c = excess thrust/weight
>
> What step do I then do to convert sin c into degrees above the horizon?
>
> TIA

xerj
January 29th 07, 11:40 AM
Ahhh that's right!

Thanks.

"Tony" > wrote in message
oups.com...
>
> You simply want to know what angle has that sine. arc sin (c) would be
> the function on the calculator you're looking for.
> On Jan 28, 5:54 pm, "xerj" > wrote:
>> I remember that sin c = excess thrust/weight
>>
>> What step do I then do to convert sin c into degrees above the horizon?
>>
>> TIA
>

Tony
January 29th 07, 12:05 PM
You can make it a little easier on yourself, for small angles just
multiply the sine by 57. For example, a 10 degree climb angle is
pretty steep. sin(10) is 0.1736. The approximation I mentioned would
return 9.9 degrees (that's because for small angles sin(angle) is
pretty much equal to tan(angle) and to the angle itself if measured in
radians.




j" > wrote:
> Ahhh that's right!
>
> Thanks.
>
> "Tony" > wrote in ooglegroups.com...
>
>
>
>
>
> > You simply want to know what angle has that sine. arc sin (c) would be
> > the function on the calculator you're looking for.
> > On Jan 28, 5:54 pm, "xerj" > wrote:
> >> I remember that sin c = excess thrust/weight
>
> >> What step do I then do to convert sin c into degrees above the horizon?
>
> >> TIA- Hide quoted text -- Show quoted text -

John T
January 29th 07, 12:33 PM
"Tony" > wrote in message
ups.com
>
> You can make it a little easier on yourself, for small angles just
> multiply the sine by 57. For example, a 10 degree climb angle is
> pretty steep. sin(10) is 0.1736. The approximation I mentioned would
> return 9.9 degrees (that's because for small angles sin(angle) is
> pretty much equal to tan(angle) and to the angle itself if measured in
> radians.

Cockpit math is hard enough. Cockpit trigonometry? Are you kdding?? :)

--
John T
http://sage1solutions.com/blogs/TknoFlyer
Reduce spam. Use Sender Policy Framework: http://openspf.org
____________________

Tony
January 29th 07, 01:08 PM
Sorry, I lost my head!

And my wife balances the checkbook. Go figure. (pun intended).

On Jan 29, 7:33 am, "John T" > wrote:
> "Tony" > wrote in oglegroups.com
>
>
>
> > You can make it a little easier on yourself, for small angles just
> > multiply the sine by 57. For example, a 10 degree climb angle is
> > pretty steep. sin(10) is 0.1736. The approximation I mentioned would
> > return 9.9 degrees (that's because for small angles sin(angle) is
> > pretty much equal to tan(angle) and to the angle itself if measured in
> > radians.Cockpit math is hard enough. Cockpit trigonometry? Are you kdding?? :)
>
> --
> John Thttp://sage1solutions.com/blogs/TknoFlyer
> Reduce spam. Use Sender Policy Framework:http://openspf.org
> ____________________

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