"Kevin Neave" k wrote in
message So ((U*U) - (V*V)) / (2*a) = s

For the light glider

V=19m/s, U=50m/s, a=7.31m/s/s

((50 * 50) - (19 * 19)) / (2 * 7.31) = 146.31 metres.
So Our height gained = 1/sqrt(2) * 146.31 = 103.46m

For the heavy glider

V=22m/s, U=50m/s, a=7.23m/s/s

((50 * 50) - (22 * 22)) / (2 * 7.23) = 139.24 metres
!! Height gained = 98.46 metres !!

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OK, So there's some assumptions in the above, but I
think all of them were made in favour of the heavy
glider.

But I say once again, for a pull up from 100kts with
100kgs of ballast, 'It's too close to call'...

Over to you Todd

:-))




Kevin.
I don't see anywhere in your in your math the higher initial rate of sink
for
the lighter ship. If you look at polars for ballasted vs empty, for any
given
speed, the rate of sink is higher unloaded. The assumption that both
gliders are at the same height when they reach the the 0 fps up point
of the pullup looks flawed in my mind. You must wait longer in the
unloaded glider to establish a climb. In fact I think the softer pullup,
the greater the difference in starting heights of the newtonian decayed
climb.

Scott.