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Old October 8th 03, 07:39 PM
Tarver Engineering
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"Ed Rasimus" wrote in message
...
On Wed, 8 Oct 2003 18:58:04 +0100, "John Mullen" wrote:

"Tarver Engineering" wrote in message
...

"Ed Rasimus" wrote in message
As I recall, the first integral of velocity is acceleration.

Nope.

I hate to say it Ed but for once Tarver is right. The first

*differential*
of velocity is acceleration. The first integral would be distance

covered. I
understood perfectly what you meant though and envy you that experience.


Well, the disclaimer at the beginning of my post should cover me. I
knew that the relationship between velocity, acceleration and rate of
change of acceleration went one way or the other.


It goes both ways:

Integral a dt = V + V0
dV/dt = a

But of course, Ed knows his airplane operating.