I hate to say it Ed but for once Tarver is right. The first *differential*
of velocity is acceleration. The first integral would be distance covered. I
understood perfectly what you meant though and envy you that experience.

Integral A dt = V0 + At =V


I've no idea what he means by this though!

John

It's basic calculus. Try this one in English units: if you drop an object the
function for determining how far it has fallen is X=16T^2, where X is the
distance travelled in feet and T is the time in seconds. The first derivative
is V = 32T where V is instantaneous velocity expressed in feet per second. The
first derivative of V, and the second of X, is A = 32 feet/second/second which
is the acceleration due to gravity. Integration is the reverse process. This
function doesn't take into account drag, but if you drop a bowling ball from
the top of a 10 story building drag is negligible.


Dan, U. S. Air Force, retired