"Montblack" wrote in message
...
("Matt Barrow" wrote)
That's indeed quite a bit, huh? If I take a 1/3lb lead ball to a C-206
flyer and tell him that's how much lead there is in his full tanks, I
bet he'll be surprised.

How big do you think that ball would be?


"I know, I know. Me. Me. Call on Me!"

http://www.tesarta.com/www/resources...y/weights.html
Lead:
[Cubic foot = 1,728 cubic inches]
710 lbs / cubic foot
1 lb. = 2.43 cubic inchs of lead
x 0.33 lbs. = 0.8 c.i. (cubic inches of lead)

http://www.1728.com/diam.htm
Volume of a sphere ..."I knew where to look it up!"

1.15 inches [Diameter] seems to be close for 0.8 cubic inches.

A 25 cent [Quarter] measures 92% of an inch across. About 15/16 - not
quite an inch. (I squinted because I needed 0.92! g)

.92 [Diameter] into the sphere equation = 0.4 c.i. (x 2) = 0.8 c.i.

So, two spheres, each with a diameter of a 25 cent [Quarter] = 0.8 cubic
inches ...which = 1/3 lb of lead. One lead ball for each side!

In the words of Don Rickles, "Very good; you win a cookie!" :~)