![]() |
If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
#1
|
|||
|
|||
![]()
Somebody posed that seemingly simple question to me, but kept coming
back to the point that they stumped me.... And I am stumped. What do you see wrong with the logic in this dialog? Q: Why do I need to lean out my carb when I climb? A: Ahem, seems you forgot your PPL ground school. The air is less dense. Fewer air molecules per unit volume. Therefore, you need less gas, so you lean it out! Q': Um, ok. Well I looked at my ground school text, and it shows how a carby operates. Apparently, avgas is kept at a constant level in a float bowl, which is vented upstream of a venturi. Air flows through the venturi, and creates a lower pressure, the resulting differential pressure forcing the avgas across an orfice and into the airstream, where it mixes it all up in a nice and precise ratio. A': OK, go on. Q'': Well, as you climb, I understand the air gets less dense. Let's assume for simplicity that the volumetric efficiency of the engine remains fixed, therefore the velocity in the venturi remains the same. Now the air is less dense, and from the previous chapter in ground school 101, the differential pressure "p" is related to the density "r" given a certain velocity "v" like this: p = 1/2 r v^2 So given a constant velocity, and a decreasing density, won't the differential pressure decrease, effectively metering less avgas across that orfice? A'': OK; I'm sure you're simplifying assumptions are too simple, you missed something there. Q''': OK, let's get a little more precise. The mass airflow rate, m, through a carby is m = c v , where c is a constant for a certain throttle setting, v is the velocity. Substituting that into the eq's above , we see that p = 1/2 r m^2 / c^2. Now we know that the mass flow rate for a liquid across an orfice is very close to proportional to the square root of the pressure drop [ I actually had to check up on this one, but it appears to be so: http://www.efunda.com/formulae/fluid..._flowmeter.cfm ] -- and of course the density of the avgas doesn't change appreciably[!]. Therefore, the avgas flow rate is proportional to "r^(1/2) m". From this point of view the carby at a constant air density can be viewed as a device that meters a constant mass proportion mixture of avgas and air, across a range of mass airflows -- ignoring the effects of accelerator pumps, full-throttle enrichers, idle circuits and all that. But note that as the density decreases, the fuel proportion to air decreases -- suggesting that one would need to ENRICH the mixture when climbing into less dense air. Assuming that the desired mass proportion of fuel/air is approximately the same across varying densities (which seems very reasonable to both of us). A''': OK, I do follow that (after some work)... and I'm stumped. Granted, some simplifying assumptions here, but no convincing explanation of why you would need to lean that red know when climbing... (and I don't question that you in fact do).... Anyone see what is amiss? T |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
Learning to lean | WingFlaps | Piloting | 2 | March 12th 08 10:47 AM |
Have you ever experienced carb ice with an injector carb? | flybynightkarmarepair | Home Built | 1 | January 31st 05 01:48 AM |
Carb temp guage vs. Iceman carb ice detector | Mike Rapoport | Piloting | 1 | September 28th 04 03:13 AM |
Whether to Lean or Enrich | jls | Owning | 12 | March 3rd 04 07:56 AM |
Leaning / step climbing? | aaronw | Piloting | 30 | November 17th 03 05:44 PM |