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#1
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![]() If a 7 amp/h battery shows 12.00 volts exactly, after 5 hours with a 5 Watt resistor, what voltage should a 10 amp/h battery show? Both batteries are of the same type and starting from the same voltage with surface charge removed. Udo |
#2
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"If a 7 amp/h battery shows 12.00 volts exactly, after 5 hours
with a 5 Watt resistor, what voltage should a 10 amp/h battery show? Both batteries are of the same type and starting from the same voltage with surface charge removed. Udo" Something seems mixed up here. Wattage is determined by multiplying the current times the voltage. Excatly 5 watts would only be dissipated during a brief period, since the voltage and the current will be changing during the discharge cycle. I am wondering if the 5 watt rating of the resistor is misleading you. What is the resistor value in ohms? The manufacturer should have a curve showing the voltage at various discharge rates vs. time. Colin |
#3
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Udo, what is the resistance of the resistor?
Larry "Zero One" USA "Udo Rumpf" wrote in message : If a 7 amp/h battery shows 12.00 volts exactly, after 5 hours with a 5 Watt resistor, what voltage should a 10 amp/h battery show? Both batteries are of the same type and starting from the same voltage with surface charge removed. Udo |
#4
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I used a 12 volt Halogen light rated at 5 watt.
The two batteries were set up at the same time and each had the identical 12 volt light, the discharge lasted for 51/2 hours and ended at 12.00 volts for the smaller battery and 12.05 volt with the bigger one. both started at 12,70 volts no resistor attached. Udo "COLIN LAMB" wrote in message nk.net... "If a 7 amp/h battery shows 12.00 volts exactly, after 5 hours with a 5 Watt resistor, what voltage should a 10 amp/h battery show? Both batteries are of the same type and starting from the same voltage with surface charge removed. Udo" Something seems mixed up here. Wattage is determined by multiplying the current times the voltage. Excatly 5 watts would only be dissipated during a brief period, since the voltage and the current will be changing during the discharge cycle. I am wondering if the 5 watt rating of the resistor is misleading you. What is the resistor value in ohms? The manufacturer should have a curve showing the voltage at various discharge rates vs. time. Colin |
#5
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The 5 watt rating would be at a specified voltage. Let us assume 12 volts
nominal. That would mean a current draw of .417 amps. I am not looking at the battery discharge cur es, but a 7 amp hour battery would normally be rated at 7 amp hours using a total discharge between something like 13.8 volts and 10.5 volts. I am just using those numbers for illustration, but most manufacturers rate the total amp-hours using an unrealistic low voltage and often a higher voltage than might be used in a glider (since it might be removed from a charger for some time). 5.5 hours at .417 amps would yield a total of 2.3 amp hours. That seems pretty consistent with the voltage drop you measured for the 7 amp hour battery. The 10 amp hour battery should be proportionally longer lived, so it should take 10/7 x 5.5 hours or 7.86 hours to arrive at the same 12 volts. Thus, it appears that the 10 amp hour battery has lost some capacity. Colin |
#6
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Udo, if the light bulb is receiving the same heat dissipation in both cases
(hanging freely in the same ambient air temperature), the time to discharge to a particular voltage should be proportional to the AH rating of similarly constructed batteries (batteries with similar discharge curves). Bob "Udo Rumpf" wrote in message .. . I used a 12 volt Halogen light rated at 5 watt. The two batteries were set up at the same time and each had the identical 12 volt light, the discharge lasted for 51/2 hours and ended at 12.00 volts for the smaller battery and 12.05 volt with the bigger one. both started at 12,70 volts no resistor attached. Udo "COLIN LAMB" wrote in message nk.net... "If a 7 amp/h battery shows 12.00 volts exactly, after 5 hours with a 5 Watt resistor, what voltage should a 10 amp/h battery show? Both batteries are of the same type and starting from the same voltage with surface charge removed. Udo" Something seems mixed up here. Wattage is determined by multiplying the current times the voltage. Excatly 5 watts would only be dissipated during a brief period, since the voltage and the current will be changing during the discharge cycle. I am wondering if the 5 watt rating of the resistor is misleading you. What is the resistor value in ohms? The manufacturer should have a curve showing the voltage at various discharge rates vs. time. Colin |
#7
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Typically, lead acid batteries of the kinds used in our applications
have amp hour ratings based on the load where it will take 20 hours to discharge the battery. In higher rate applications, like running that light bulb, amp-hour capacity performance is normally degraded. The degradation may not scale linearly so comparisons between 2 different packs may not work out using straight ratios. Capacity curves as well as voltage curves for the batteries at various discharge rates should be available on-line at the manufacturer's web site. Other things to consider... The charging requirement for the different capacity packs may vary. Are the batteries each fully charged at the start of the test? How consistent are the 2 bulbs you are using? Could 1 bulb be drawing more current than the other? Capacity does drop off with use. Capacity could also be adversly affected by abuse such as deep discharge. Could the use (or abuse) history alter the expected results? Danny Brotto LS-8-18 "P6" |
#8
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The resistance of filament lamps is current dependent. I think you'd
have a better comparison test if used used a fixed value resistor. Andy |
#9
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The resistance of filament lamps is current dependent. I think you'd
have a better comparison test if used used a fixed value resistor. Andy |
#10
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The resistance of filament lamps is current dependent. I think you'd
have a better comparison test if used used a fixed value resistor. Although it is true the resistance of a lamp changes with applied voltage, it is not an issue since the current flowing through a fixed resistor will change as the voltage decreases. As the voltage decreases, current decreases. As a matter of fact, as the voltage on the lamp decreases, the temperature of the filament will decrease, which will decrease the resistance, which will increase the current drawn. Thus, the lamp should result in more constant current flow and improve the accuracy of a constant current graph. If you start at a certain voltage and discharge to a defined ending voltage, it should not matter whether your resistance is slightly variableor fixed. In neither case will you have a constant discharge, which is often what the hypothetical battery discharge graph imagines. I have used lamps successfully for years to check out batteries. The secret is to select a lamp with the same current draw as the equipment you are using. You can glance over at the lamp and see that all is well. Colin |
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