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#1
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I have a thermometer that reads from 0 to 200°F. I'm trying to measure a
cylinder head on an aircooled engine where my range of interest goes from, say, 200 to 400°F. The classic way of measuring this temperature is with a thermocouple mounted on a copper washer underneath the spark plug of the cylinder that you determine (by trial and error) to be the hottest. I can think of several ways of measuring a cooler spot on the cylinder that will probably be in rough proportion to the actual temperature at the plug seat, but most of them are dependent on the airflow over the cylinder(s) remaining constant from day to day. With the baffling on the engine being rather thin and wobbly, I can't count on this airflow being truly constant. The sensor on my thermometer is a plain old silicon diode that won't directly take the heat that I'm trying to measure. Anybody got a clever way of making a thermal divider that won't be subject to the day to day shuffle of the airflow over the cylinders? Jim |
#2
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RST Engineering (jw) wrote:
a thermal divider that won't be subject to the day to day shuffle of the airflow over the cylinders? Jim Attach the sensor to a piece of metal. Bolt the metal to something on the cylinder head. Wrap the metal/sensor with insulating tape to keep cooling air off it. Change the size of the metal piece to vary the temperature ratio. -- John Kimmel remove x "He's dead, Jim." |
#3
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Is it purely a function of the size of the metal piece, or is the type of
metal part of the equation? The other thing I don't understand is that if I do a good job of insulating the metal piece from ambient how it won't eventually come to the same temperature as the head. Thermo and I never did get along very well. Jim "John Kimmel" wrote in message ... RST Engineering (jw) wrote: a thermal divider that won't be subject to the day to day shuffle of the airflow over the cylinders? Jim Attach the sensor to a piece of metal. Bolt the metal to something on the cylinder head. Wrap the metal/sensor with insulating tape to keep cooling air off it. Change the size of the metal piece to vary the temperature ratio. -- John Kimmel remove x "He's dead, Jim." |
#4
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![]() RST Engineering (jw) wrote: I have a thermometer that reads from 0 to 200°F. I'm trying to measurea cylinder head on an aircooled engine where my range of interest goes from, say, 200 to 400°F. The classic way of measuring this temperature is with a thermocouple mounted on a copper washer underneath the spark plug of the cylinder that you determine (by trial and error) to be the hottest. I can think of several ways of measuring a cooler spot on the cylinder that will probably be in rough proportion to the actual temperature at the plug seat, but most of them are dependent on the airflow over the cylinder(s) remaining constant from day to day. With the baffling on the engine being rather thin and wobbly, I can't count on this airflow being truly constant. The sensor on my thermometer is a plain old silicon diode that won't directly take the heat that I'm trying to measure. Anybody got a clever way of making a thermal divider that won't be subject to the day to day shuffle of the airflow over the cylinders? Why don't you get a better sensor? Either a thermocouple or a platinum resistance sensor will go up to 400F (204C). Farnell do a thin-film Pt100 sensor that is only 5 mm by 2mm by 1.1mm. Omega do similar looking sensor with leads attached (good o 500F) http://www.omega.com/ppt/pptsc.asp?r...D-2&Nav=temc06 -- Bill Sloman, Nijmegen |
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RST Engineering (jw) wrote:
Is it purely a function of the size of the metal piece, or is the type of metal part of the equation? The other thing I don't understand is that if I do a good job of insulating the metal piece from ambient how it won't eventually come to the same temperature as the head. Thermo and I never did get along very well. Jim The insulation is to shield the sensor and heat sink from the effects of transient airflow. The insulation won't be perfect in any case, but you can vary the amount of insulation and the size of the heat sink to vary your results. If the insulation is perfect, then you will need to bolt the heat sink to something that doesn't get very hot. This idea might not work at all, but it is something that would be easy to try, and easy to change variables on. -- J Kimmel www.metalinnovations.com "Cuius testiculos habes, habeas cardia et cerebellum." - When you have their full attention in your grip, their hearts and minds will follow. |
#6
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RST Engineering (jw) wrote:
Is it purely a function of the size of the metal piece, or is the type of metal part of the equation? The other thing I don't understand is that if I do a good job of insulating the metal piece from ambient how it won't eventually come to the same temperature as the head. If you mount the sensor in a bar that is picking up heat at one end, and losing heat at the other - you sensor will read somewhere between the two temperatures. But, if you don't know a lot about the heat transfer rates at each end, you will not know how the temperature your sensor sees is related to the temperature you want to measure. Think of a series voltage divider with two known resistors in the middle and an unknown resistor attached to each end. What does the votage measured at the junction between the two known resistors tell you about the source voltage? -- Geoff The Sea Hawk at Wow Way d0t Com remove spaces and make the obvious substitutions to reply by mail When immigration is outlawed, only outlaws will immigrate. |
#7
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If you mount the sensor in a bar that is picking up heat at one end, and
losing heat at the other - you sensor will read somewhere between the two temperatures. But, if you don't know a lot about the heat transfer rates at each end, you will not know how the temperature your sensor sees is related to the temperature you want to measure. That's exactly the point, Geoff. When I do a resistive divider, it is always between two "hard" voltages, either a variable voltage and a reference voltage or a variable voltage and ground. I know what the reference is and can easily calculate the variable. The thermal reference is not quite so trivial. It is a function of airflow, ambient temperature, and phase of the moon. Think of a series voltage divider with two known resistors in the middle and an unknown resistor attached to each end. What does the votage measured at the junction between the two known resistors tell you about the source voltage? Absolutely nothing. An equation in one unknown with two degrees of freedom is insoluble. There are an infinite number of correct answers and an infinite number of incorrect answers. HOWEVER, if you let me measure the voltage ACROSS one of those known resistors and THEN the voltage at the junction, I've got a fighting chance if you know what the bottom end resistor is tied to. Jim |
#8
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"RST Engineering" wrote in message
news ![]() Think of a series voltage divider with two known resistors in the middle and an unknown resistor attached to each end. What does the votage measured at the junction between the two known resistors tell you about the source voltage? Absolutely nothing. An equation in one unknown with two degrees of freedom is insoluble. There are an infinite number of correct answers and an infinite number of incorrect answers. HOWEVER, if you let me measure the voltage ACROSS one of those known resistors and THEN the voltage at the junction, I've got a fighting chance if you know what the bottom end resistor is tied to. Think of heat flow as current, temperature as voltage, the actual connecton between your divider and the heat source / sink like unknown resistors (area, contact, material all make a difference as in a high current circuit) your bar with the sensor in the middle is like the voltage drop in a transmission line - flow is a function of area, material, potential. Heat loss from the bar is a little harder - I guess in a high tension transmission line there is some leakage to ground across the insulators? And you thought you didn't know thermodynamics... fwiw, I think I would just buy a different sensor, eh? -- Geoff The Sea Hawk at Wow Way d0t Com remove spaces and make the obvious substitutions to reply by mail When immigration is outlawed, only outlaws will immigrate. |
#10
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"Capt. Geoffrey Thorpe" The Sea Hawk at wow way d0t com wrote in message
news ![]() RST Engineering (jw) wrote: Is it purely a function of the size of the metal piece, or is the type of metal part of the equation? The other thing I don't understand is that if I do a good job of insulating the metal piece from ambient how it won't eventually come to the same temperature as the head. If you mount the sensor in a bar that is picking up heat at one end, and losing heat at the other - you sensor will read somewhere between the two temperatures. But, if you don't know a lot about the heat transfer rates at each end, you will not know how the temperature your sensor sees is related to the temperature you want to measure. Think of a series voltage divider with two known resistors in the middle and an unknown resistor attached to each end. What does the votage measured at the junction between the two known resistors tell you about the source voltage? how about two temp sensors at measured intervals along the insulated bar, then assuming the temperature gradient is constant along the bar, you can work out the temp at the cylinder head. Colin =^.^= |
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