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#11
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yap yap yap ypa
The Speedbyrd : Yes I have always admired your helpful and intelligent inputs here. Don't bother replying as I have an excellent killfile :-) --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.545 / Virus Database: 339 - Release Date: 27/11/2003 |
#12
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Sorry, I was indeed sleeping a bit with the weight thing. Too many years
since I had to mess too much with it. ![]() But please notice that I never EVER said that I was saying how to climb the fastest (either covering the least amount of distance when climbing, nor gaining altitude as fast as possible, nor reach altitude using as little fuel as possible). Basically your long statement of how wrong I was is based on trying to acheive the most efficiant climb - which I never stated it was. Just like you trid to make it look like I thought a flight model can be judged from one single messurement. Obviously I never stated that, and obviously I never meant it, so why comment on it as if I made a mistake? I can see you might interprete my "maximum lift" statement as "maximum climb" - it is not how I read it, but I agree - it is a bit "on the edge", I will give you that. If you take this into account, along with the fact that I was trying to explain a simple way of reaching max speed, I still claim my original information is good enough to reach the ceiling - and that was what this question was about, the rest you made up. /Lars |
#13
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"Lars Møllebjerg" wrote in message
... But please notice that I never EVER said that I was saying how to climb the fastest [...] Basically your long statement of how wrong I was is based on trying to acheive the most efficiant climb - which I never stated it was. No. You said that to climb, one needed to fly at the maximum speed for the given altitude. This is simply wrong. The maximum speed for any given altitude will NOT produce a climb. Just like you trid to make it look like I thought a flight model can be judged from one single messurement. Obviously I never stated that, and obviously I never meant it, so why comment on it as if I made a mistake? I didn't "try to make it look like" anything. You said "this is the configuration where you should compare it to the real world aircraft to see how well the model is done". In my reply, I even refrained from saying that you were flat out wrong. I simply agreed that the "data point" you described was useful, but pointed out it was not sufficient. If anything, I gave way more benefit of the doubt than your post deserved. I can see you might interprete my "maximum lift" statement as "maximum climb" - it is not how I read it, but I agree - it is a bit "on the edge", I will give you that. The point is that the phrase "maximum lift" is meaningless. You get the same amount of lift at any airspeed for normal, unaccelerated flight. If you take this into account, along with the fact that I was trying to explain a simple way of reaching max speed, I still claim my original information is good enough to reach the ceiling - and that was what this question was about, the rest you made up. "The rest you made up"? Funny. Bottom line: your advice, to fly at maximum speed, won't allow the airplane to climb at all, never mind reach the airplane's ceiling. I understand your desire to save face, but revisionist history just doesn't cut it on Usenet. Anyone can go back to your previous post to see what you really said. Pete |
#14
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On Mon, 08 Dec 2003 02:32:58 -0600, R wrote:
With the SR-71, I mostly climb with the autopilot. Granted, I usually set at the default 1,100 fpm climb rate, but I didn't think that would be too much of a problem for the fastest (known) plane in the world, a plane that pulls Mach 3.3 at 80,000 feet. At some point well before 80,000 feet, the autopilot more or less fails, pulling the nose up into a stall. Checck WWW for somew real-life SR-71 procedures. Get her supersonic at 30.000 ft (this means an IAS of about 600 kts...!!!!)... and keep that IAS during a shallow climb. Adjust the climb rate accordingly - most important is to keep IAS. The higher you climb, the higher gets your MACH - until you level off at 70.000 ft with an IAS of abpout 600 kts at Mach 3.x. Bye Andreas |
#15
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On Sun, 7 Dec 2003 at 12:41:21 in message
, Lars Møllebjerg wrote: By the way, saying that lift is equal to weight is a bit wierd as the lift is a force generated, while weight isn't a force, but a number calculated from the mass and gravity. But I guess it's one of those simplification making it easier for people to understand. ![]() I presume you are referring to Newton's laws. However if you want to be pedantic then you are wrong. Weight is a force, Mass isn't. We had a famous popular scientist who used to ask "how much does a satellite weigh in orbit?" His answer is zero although its mass remains the same. Two forces are cancelling out in orbit. Weight _is_ a force, although it is a restricted case that refers only to the force that is generated by gravity. In what way does this 'simplification' make any difference to the equations? Of course lift only equals weight in steady straight and level flight. -- David CL Francis |
#16
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"David CL Francis" wrote in message
... Its mass is the same; its weight differs. You are still being confused between weight and mass. It is true that its weight differs. It's farther from the Earth's center of gravity, thus the weight is necessarily less. However, I think what Jeffrey was trying to point out is that the satellite still does *weigh* something. And in fact, its weight is almost as great as it would be sitting on the surface of the Earth. Weight is the measure that you find if you weigh something on a spring balance. I think this view of "weight" is what's tripping you up. The satellite in freefall would appear to weigh nothing if weighed on a weighing scale that is also in freefall with the satellite. However, that doesn't mean that the satellite weighs nothing. In fact, if it weren't for its weight, it would fly off at a tangent to its orbit. The satellite's weight is what keeps it in orbit. It's just not true that the satellite weighs zero in orbit. It's my impression that this is what Jeffrey was saying in his post. Mass is a measure of the total quantity of matter in an object. If you are floating in deep space in free fall, then you cannot detect any weight. Detecting weight and the existence of weight are two different things. Consider the folks riding the "Vomit Comet", the jet used to create freefall conditions without going into orbit. The occupants of the aircraft during its parabolic flight cannot detect their weight. However, it is their very weight that keeps them accelerating toward the planet, as it always does during the non-parablic phases of flight or even while standing on solid ground. However the _mass_ is the same and if a force (perhaps from a rocket motor} is applied then the acceleration depends on the force exerted by the rocket and the mass of the object. I'm not sure what this has to do with the so-called "weightless satellite". Some of the confusion arises because in the imperial system of units there is no obvious distinction in the measurement of them. I'm not sure that explains your confusion regarding whether a satellite in orbit is weightless or not. For ordinary everyday, stuck on the surface of earth, people the distinction is subtle. To engineers, physicists and applied mathematicians the distinction is essential. Which is why it's odd you seem to think that a satellite in orbit is weightless. It's not. Pete |
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Peter Duniho wrote:
[confused stuff on weight snipped] Sorry, but you are confusing mass and weight. There is no such thing as weight. Weight is a nebulous term that non-physicists use to describe gravitational attraction between two bodies, or so it seems to me. A body has mass and velocity; that's all it has, it doesn't have weight. No reflection on PD, since we all did different things at school, but this is plain-vanilla high-school physics. A satellite has no weight in orbit; it has mass and velocity (and therefore momentum). The reason it doesn't fly off on a tangent is because of the gravitational attraction between the mass of the Earth and the mass of the satellite, exactly counter-balancing the satellite's momentum which would act to keep it going in a straight line. Similarly, in the Vomit Comet it is not weight that is attracting the people towards the ground, it is the gravitational attraction between the mass of the Earth and the mass of the people. -- Nick |
#18
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On Sun, 14 Dec 2003 at 13:08:32 in message
, Peter Duniho wrote: "David CL Francis" wrote in message ... Its mass is the same; its weight differs. You are still being confused between weight and mass. It is true that its weight differs. It's farther from the Earth's center of gravity, thus the weight is necessarily less. However, I think what Jeffrey was trying to point out is that the satellite still does *weigh* something. And in fact, its weight is almost as great as it would be sitting on the surface of the Earth. That is mass you are talking about. I defined weight earlier. But why 'almost' in your world? Weight is the measure that you find if you weigh something on a spring balance. I think this view of "weight" is what's tripping you up. The satellite in freefall would appear to weigh nothing if weighed on a weighing scale that is also in freefall with the satellite. However, that doesn't mean that the satellite weighs nothing. In fact, if it weren't for its weight, it would fly off at a tangent to its orbit. It is not a 'view' it is definition to help to try and help you understand the difference between force and mass. I am not the list bit 'tripped up'. The satellite's weight is what keeps it in orbit. It's just not true that the satellite weighs zero in orbit. It's my impression that this is what Jeffrey was saying in his post. Once more, it is the satellite's MASS that keeps it in orbit and the MASS of the earth.. Mass is a measure of the total quantity of matter in an object. If you are floating in deep space in free fall, then you cannot detect any weight. Detecting weight and the existence of weight are two different things. Consider the folks riding the "Vomit Comet", the jet used to create freefall conditions without going into orbit. The occupants of the aircraft during its parabolic flight cannot detect their weight. However, it is their very weight that keeps them accelerating toward the planet, as it always does during the non-parablic phases of flight or even while standing on solid ground. You are talking mass again. Weight is a force, Mass is the _quantity_ of material in an object. However the _mass_ is the same and if a force (perhaps from a rocket motor} is applied then the acceleration depends on the force exerted by the rocket and the mass of the object. I'm not sure what this has to do with the so-called "weightless satellite". Some of the confusion arises because in the imperial system of units there is no obvious distinction in the measurement of them. I'm not sure that explains your confusion regarding whether a satellite in orbit is weightless or not. For the last time - I am not confused. For ordinary everyday, stuck on the surface of earth, people the distinction is subtle. To engineers, physicists and applied mathematicians the distinction is essential. Which is why it's odd you seem to think that a satellite in orbit is weightless. It's not. I give up. Get a book on physics or applied mechanics. Perhaps someone else might be able to help. You seem to be stuck with your preconceived idea as to what weight and mass are, or to put it another way as to what a force and a mass are. If I mention that force is a vector quantity (weight is a force) and that mass is a scalar quantity, I suppose that will mean nothing to you? A quote from an A level physics book: ~~~~~~begin quote~~~~~~~~~~ The weight of a body is the force of gravity acting on it towards the centre of the earth. Weight is thus a _force_ , not to be confused with mass which is independent of the presence or absence of the earth. ~~~~~~~~~~~~~end quote~~~~~ The Gravitational force F between two particles of masses m1 and m2 , a distance r apart ,is given by; F=(G*m1*m2)/r^2 where G is the Gravitational constant. -- David CL Francis |
#19
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"David CL Francis" wrote in message
... That is mass you are talking about. I defined weight earlier. But why 'almost' in your world? That is not mass I'm talking about. It's weight, and the reason it's "almost" the same as on the ground is that weight depends both on the masses of the two objects being considered as well as the distance between them. Weight decreases with the square of the distance. It is not a 'view' it is definition to help to try and help you understand the difference between force and mass. I am not the list bit 'tripped up'. So you say. The satellite's weight is what keeps it in orbit. It's just not true that the satellite weighs zero in orbit. It's my impression that this is what Jeffrey was saying in his post. Once more, it is the satellite's MASS that keeps it in orbit and the MASS of the earth.. The mass only keeps it in orbit inasmuch as mass near another mass causes a force. This force is weight, and the satellite in orbit has this force called weight. Without the weight, the satellite would fly off in a straight line. The acceleration due to weight is the only thing that allows the satellite to follow a curved path. [...] However, it is their very weight that keeps them accelerating toward the planet, as it always does during the non-parablic phases of flight or even while standing on solid ground. You are talking mass again. Weight is a force, Mass is the _quantity_ of material in an object. No, I'm talking weight. Mass is not a force. The acceleration toward Earth is caused by a force. What force? Weight. For the last time - I am not confused. Yes, you keep saying that. And yet... I give up. Get a book on physics or applied mechanics. Perhaps someone else might be able to help. You seem to be stuck with your preconceived idea as to what weight and mass are, or to put it another way as to what a force and a mass are. So you say. And yet, that's not really the problem here. If I mention that force is a vector quantity (weight is a force) and that mass is a scalar quantity, I suppose that will mean nothing to you? I know the difference between a vector and a scalar. So? A quote from an A level physics book: ~~~~~~begin quote~~~~~~~~~~ The weight of a body is the force of gravity acting on it towards the centre of the earth. Weight is thus a _force_ , not to be confused with mass which is independent of the presence or absence of the earth. ~~~~~~~~~~~~~end quote~~~~~ How does that contradict my statement that the satellite in orbit DOES have weight? The satellite in orbit is affected by the force of gravity acting on it towards the center of the Earth. Your quote defines this as "weight". By your own quote, the satellite DOES have weight. The Gravitational force F between two particles of masses m1 and m2 , a distance r apart ,is given by; F=(G*m1*m2)/r^2 where G is the Gravitational constant. I am quite aware of that. You'll notice that this gravitational force is the same as weight. You'll also notice that nowhere in that equation is there any term that would differentiate between a satellite in orbit and a satellite sitting motionless at the same distance from the planet. Both satellites wind up with the same "F", and that "F" is their weight. So, please...I'd love to hear you try to explain again why it is the satellite in orbit has no weight. Pete |
#20
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On Mon, 15 Dec 2003 at 17:52:06 in message
, Peter Duniho wrote: No, I'm talking weight. Mass is not a force. The acceleration toward Earth is caused by a force. What force? Weight. A large amount of quote is not necessary here. The object in orbit or in any trajectory around a massive object is in free fall. The path of the object caused by gravitational attraction means that there is no force measurable on the object (If you happened to be part of it.) If we want to be very precise then you might detect the gravitational gradient across the object if it had significant dimensions. Otherwise, except by external observations, you would be unable to detect acceleration to provide 'weight'. No one denies the force of gravity except in the sense that other theories claim that the effect of a large mass is to distort space. I see now at last what you are talking about, but to call the force of gravity 'weight' seems curious to me. Weight cannot be detected except when a body is not in free fall. So in orbit an object has no weight. Gravity enables 'weight' on objects that are on the surface of a body to be measured. Astronauts cannot weigh things in orbit. -- David CL Francis |
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