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#101
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Michael Ash wrote:
The original question specified "trimmed at 110 knots" which implies that the autopilot is not engaged. Correct. The question was asked about two weeks ago by the examiner in an initial CFI oral. The simple answer that worked was "about 110 knots." I talked to the guy who passed the checkride yesterday. If he had tried to give a more complicated answer and he was incorrect on anything he said, he'd have been digging his own hole. Instead, the examiner moved on and said "I'm a student and I was supposed to study and prepare for pylon 8's but I didn't do my assigned homework, so teach me from the beginning." (My wife's pragmatic response would have been "Come back when you've completed your assigned homework.") Fortunately he had a lesson plan prepared on p-8's. -c |
#102
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On Jun 4, 10:42*am, Dudley Henriques wrote:
Below is a very well done white paper on stability by Russel Williams that addresses much of what we have been discussing. The link does not work, and I can't find it through google. Do you have another link? The long and short of it in my opinion is that positive lateral stability is present in GA airplanes As lond as you mean static stability, then yes - weak positive lateral stability is present in most non-aerobatic (and a few aerobatic) GA airplanes as long as the displacement from wings-level is small. and they will tend to recover from the sideslip coupling. Again, as long as the displacement is small and the lateral trim is near-perfect. Your key point addresses potential disturbances that can indeed exceed this recovery tendency. I agree totally with you that such a disturbance can exceed positive stability tendencies if strong enough. And I guess my point is that in most cases, these disturbances will be strong enough, especially in an airplane that can cruise 110 kt. I think this is something easy enough to prove in most cases. For those playing along on the home game, try this next time you fly. Do this on the smoothest possible day you can get. Set up the plane in cruise at 110 kt. Trim it out as well as you can, both in pitch, and, if aileron and/or rudder trim is available, in roll as well. My guess is that most airplanes that can cruise 110 kt will have aileron or rudder trim available - I can't off the top of my head think of any certificated exceptions to this (I am sure there is one). Let go of the controls. All of them - hands off the yoke/stick and feet off the rudders - and just sit there. Note how long it takes to exceed 25 degrees of bank or change heading by 90 degrees. If in 15 minutes that doesn't happen, smoothly bring the throttle to idle to simulate fuel exhaustion. Let the plane descend 2000 ft or so (use carb heat if appropriate). Now see if you are still within 25 degrees of wings level. The reason this matters - generally the engine is offset just enough that at cruise, you should need no rudder. On takeoff the left-turning (for CW engines) tendencies are increased, so you need some right rudder. On a power-off descent, you need some left rudder. Yaw and roll are coupled. So even if you were in perfect lateral trim before you went to idle, you're not anymore. Now I'm willing to bet that at least 9 out of 10 people who try this will find that the plane won't fly level for 15 minutes without pilot input, and of the few that do, the engine coming back to idle will change the yaw enough that more than half the rest will enter a spiral. Michael |
#103
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On Jun 5, 1:19 pm, Michael wrote:
On Jun 4, 10:42 am, Dudley Henriques wrote: Below is a very well done white paper on stability by Russel Williams that addresses much of what we have been discussing. The link does not work, and I can't find it through google. Do you have another link? The long and short of it in my opinion is that positive lateral stability is present in GA airplanes As lond as you mean static stability, then yes - weak positive lateral stability is present in most non-aerobatic (and a few aerobatic) GA airplanes as long as the displacement from wings-level is small. and they will tend to recover from the sideslip coupling. Again, as long as the displacement is small and the lateral trim is near-perfect. Your key point addresses potential disturbances that can indeed exceed this recovery tendency. I agree totally with you that such a disturbance can exceed positive stability tendencies if strong enough. And I guess my point is that in most cases, these disturbances will be strong enough, especially in an airplane that can cruise 110 kt. I think this is something easy enough to prove in most cases. For those playing along on the home game, try this next time you fly. Do this on the smoothest possible day you can get. Set up the plane in cruise at 110 kt. Trim it out as well as you can, both in pitch, and, if aileron and/or rudder trim is available, in roll as well. My guess is that most airplanes that can cruise 110 kt will have aileron or rudder trim available - I can't off the top of my head think of any certificated exceptions to this (I am sure there is one). Let go of the controls. All of them - hands off the yoke/stick and feet off the rudders - and just sit there. Note how long it takes to exceed 25 degrees of bank or change heading by 90 degrees. If in 15 minutes that doesn't happen, smoothly bring the throttle to idle to simulate fuel exhaustion. Let the plane descend 2000 ft or so (use carb heat if appropriate). Now see if you are still within 25 degrees of wings level. The reason this matters - generally the engine is offset just enough that at cruise, you should need no rudder. On takeoff the left-turning (for CW engines) tendencies are increased, so you need some right rudder. On a power-off descent, you need some left rudder. Yaw and roll are coupled. So even if you were in perfect lateral trim before you went to idle, you're not anymore. Now I'm willing to bet that at least 9 out of 10 people who try this will find that the plane won't fly level for 15 minutes without pilot input, and of the few that do, the engine coming back to idle will change the yaw enough that more than half the rest will enter a spiral. Michael If this worked reliably, it would be taught as a standard technique for inadvertant VFR into IFR excursions. Hey, just throttle to idle, hands off and wait for VFR to appear. But....this is not what is taught. Wonder why??? This is curiously close to a technique for spin recovery that is taught for certain aerobatic airplanes such as the Pitts and the Extra, called Muller-Beggs. In this method, if you find yourself in a spin and you can't figure out what to do, then throttle to idle, hands off the stick and full rudder to counter the apparent yaw you see directly out the front, wait patiently for the spin to stop, then neutralize rudder and recover from the dive. This does NOT work for all aerobatic aircraft. One I'm personally familiar with that does not work is the Yak-54. K l e i n |
#104
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Michael Ash wrote:
Hilton wrote: Michael Ash wrote: In a steady *spiral* dive the wing loading will be determined by your bank angle. Can you prove that? (mathematically or non-mathematically) If it's steady, i.e. constant speed, then the loading will be equal to the arccosine of the bank angle, because you need to generate 1 gee straight up to counterbalance gravity. This is the same situation as a level turn, and the math and vectors should be discussed in any introductory book on flying. Your 'proof' above is almost correct for *level* flight (it ignores attitude etc, but I don't want to knit pick), however, it is not appropriate at all in a spiral even if the aircraft is at a constant speed. In a spiral, there is a non-zero component of vertical drag, therefore less vertical lift is required. However, your lift vector is now at an angle to the vertical. You cannot ignore these. Therefore the wing loading is also a function of the coefficient of drag, and perhaps other things, but clearly not only determined by your bank angle. Hilton |
#105
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In rec.aviation.student K l e i n wrote:
If this worked reliably, it would be taught as a standard technique for inadvertant VFR into IFR excursions. Hey, just throttle to idle, hands off and wait for VFR to appear. But....this is not what is taught. Wonder why??? One reason that comes to mind is that you have no guarantee that the ceiling under your IMC condition is high enough to allow for recovery. -- Mike Ash Radio Free Earth Broadcasting from our climate-controlled studios deep inside the Moon |
#106
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Michael Ash wrote in news:1212717258.920305
@web1.segnet.com: In rec.aviation.student K l e i n wrote: If this worked reliably, it would be taught as a standard technique for inadvertant VFR into IFR excursions. Hey, just throttle to idle, hands off and wait for VFR to appear. But....this is not what is taught. Wonder why??? One reason that comes to mind is that you have no guarantee that the ceiling under your IMC condition is high enough to allow for recovery. Well, "inadvertant flight into IMC" is almost always a push on regardless scenario where the pilot gets lower and lower, often in inhospitable terrain, so it'd be kind of useless in that anyway. Bertie |
#107
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On 2008-06-06, Michael Ash wrote:
In rec.aviation.student K l e i n wrote: If this worked reliably, it would be taught as a standard technique for inadvertant VFR into IFR excursions. Hey, just throttle to idle, hands off and wait for VFR to appear. But....this is not what is taught. Wonder why??? One reason that comes to mind is that you have no guarantee that the ceiling under your IMC condition is high enough to allow for recovery. ....especially if there's cumulo-granite or cumulo-steel inside. -- Jay Maynard, K5ZC http://www.conmicro.com http://jmaynard.livejournal.com http://www.tronguy.net Fairmont, MN (FRM) (Yes, that's me!) AMD Zodiac CH601XLi N55ZC (ordered 17 March, delivery 10 June) |
#108
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In rec.aviation.student Jay Maynard wrote:
On 2008-06-06, Michael Ash wrote: In rec.aviation.student K l e i n wrote: If this worked reliably, it would be taught as a standard technique for inadvertant VFR into IFR excursions. Hey, just throttle to idle, hands off and wait for VFR to appear. But....this is not what is taught. Wonder why??? One reason that comes to mind is that you have no guarantee that the ceiling under your IMC condition is high enough to allow for recovery. ...especially if there's cumulo-granite or cumulo-steel inside. Just so. Reading my own post it occurs to me that "IMC condition" is one of those redundant uses of acronyms, like "ATM machine" or "PIN number". My apologies for any annoyance this may have caused. ![]() -- Mike Ash Radio Free Earth Broadcasting from our climate-controlled studios deep inside the Moon |
#109
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On Jun 5, 4:01*pm, K l e i n wrote:
If this worked reliably, it would be taught as a standard technique for inadvertant VFR into IFR excursions. *Hey, just throttle to idle, hands off and wait for VFR to appear. *But....this is not what is taught. *Wonder why??? Well, two reasons. One, because there is no guarantee that you will reach stability in a bank without exceeding Vne (and in fact in many airplanes you will not - wings or tail will come off). Two, because recovery from a spiral dive actually takes a fair amount of altitude, and trying to do it quickly will likely break something as you will be well above Va. This is curiously close to a technique for spin recovery that is taught for certain aerobatic airplanes such as the Pitts and the Extra, called Muller-Beggs. Well, OK - but it's not a technique at all. It is simply a demostration that the airplane will not remain wings level at trim speed without pilot input for very long, expecially in the event of engine failure. Quite the contrary, an active recovery will most likely be necessary. If the demostration is wrong, then the plane WILL remain wings level (the way a ram-air parachute will). Now THAT would be useful for inadvertent IMC encounters. Just tell people to let go of the controls, and the plane will fly out of it. In fact, that is exactly what parachutists do if they inadvertently encounter a cloud. Michael |
#110
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