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 If I haven't completely mangled this then, the probability of 
		
	
		
		
		
		
		
	
		 
		
	
	
	surviving through TWO sequential occurrences of an event, each occurrence of which carries a 9-in-10 probability, is: .9 * .9 = .81 If one were to survive through these two trials and try a third the odds of surviving all three would be: .9 * .9 * .9 = .729 Doesn't look good for an event with a 1-in-10 chance of dying! Have I got this sorted out? Yep. And you even got the part about multplying survival rates rather than death rates (a sometimes subtle point - the sequence depends on multple survivals, not multple deaths) Jose -- Quantum Mechanics is like this: God =does= play dice with the universe, except there's no God, and there's no dice. And maybe there's no universe. for Email, make the obvious change in the address.  | 
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