Fly It to the Ground

"Peter Duniho" wrote:
9G deceleration is 32 feet/s/s times 9, or almost 300 feet/s/s. 1 mph
is about 1.5 f/s. To lose 50 mph (roughly 75 f/s) at 9G would take
75/300 = 1/4 second. In 1/4 second, constant deceleration from 75
f/s, you'd travel (75/2)/4 feet, or 9 feet.

No need to compute the deceleration time (intermediate result) if one
applies a little algebra (or calculus):

S = V*V/(2*a)

S = Distance traveled.
V = Initial velocity.
a = Deceleration.

The mistakes people seem to make normally come from unit conversion (e.g.
mph to fps).