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#1
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Anyone tell me at what altitude I get 75% and 65% power respctively
(with full throttle, normally aspirated). |
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#2
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You don't have a POH?
On 10/21/2006 10:33 AM, Doug wrote the following: Anyone tell me at what altitude I get 75% and 65% power respctively (with full throttle, normally aspirated). |
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#3
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Doug wrote
Anyone tell me at what altitude I get 75% and 65% power respctively (with full throttle, normally aspirated). See the graph at: http://www.kellyaerospace.com/articl...bocharging.pdf Bob Moore |
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#4
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Mitty wrote
You don't have a POH? You know, he might not even have an airplane. He just asked a question and expected an answer, not a wise crack. No POH required, answer is not aircraft specific, see: http://www.kellyaerospace.com/articl...bocharging.pdf Bob Moore |
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#5
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In article .com,
"Doug" wrote: Anyone tell me at what altitude I get 75% and 65% power respctively (with full throttle, normally aspirated). Depends on the engine, depends on the OAT (density altitude). |
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#6
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john smith wrote
Depends on the engine, depends on the OAT (density altitude). Not on the engine as long as it's "normally aspirated' as specified in the OP. Bob Moore |
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#7
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5 and 7 thousand
"Doug" wrote in message oups.com... | Anyone tell me at what altitude I get 75% and 65% power respctively | (with full throttle, normally aspirated). | |
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#8
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Jim Macklin wrote
5 and 7 thousand Running on (faulty) memory again, Jim? How about 7,500' and about 12,500', ISA of course. See my previous replies to this thread for a real chart answer. The formula answer is: bhp at altitude equals bhp at sea level times the quantity (density ratio minus the quantity(1 minus density ratio divided by 7.55)) Works out to 76% at 7,500' and 64% at 12,500', or thereabouts. Bad information is worse than no information at all. Bob Moore |
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#9
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In article ,
Bob Moore wrote: The formula answer is: bhp at altitude equals bhp at sea level times the quantity (density ratio minus the quantity(1 minus density ratio divided by 7.55)) Works out to 76% at 7,500' and 64% at 12,500', or thereabouts. OK, I'm confused. Full throttle, 64%, is 12,500' for any engine? How come my cherokee 140 couldn't even get to 12,500'? What am I overlooking? -- Bob Noel Looking for a sig the lawyers will hate |
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#10
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Bob Noel wrote
Bob Moore wrote: Works out to 76% at 7,500' and 64% at 12,500', or thereabouts. OK, I'm confused. Full throttle, 64%, is 12,500' for any engine? How come my cherokee 140 couldn't even get to 12,500'? What am I overlooking? :-) The wing, of course. :-) Bob Moore |
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