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You're right about a barrel roll, of course, I like that you can
rotate the wings through 360 degrees and maintain 1 G. You could also, I think, start the 'roll' with an upward velocity component of 320 feet a second and end it level, but hardly at the same altitude (you'd be 1600 feet higher). An even more interesting question would be, is there an airplane that can fly this flight path? I think it would take massive control surfaces to be able to pull a G with the yoke. On Jun 14, 9:55 pm, Matt Whiting wrote: wrote: Jim, you don't have to do the physics for a 1 g roll. click on stanford.edu/~sigman/one_g_roll.html for a really neat analysis. Page down toward the end of sigman's article to see the actual flight paths that it takes. It's a neat read. Oh, for the nonbelievers in Newton and vector analysis and such (Mx whatever comes to mind) don't bother. A very nice analysis and it confirms that you can't execute a barrel roll from straight and level flight while maintaining 1G. You either lose a lot of altitude and end up in a steep dive or you have to pull up (and thus exceed 1 G) if you want to end up at the starting altitude. Case closed. :-) Matt |
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Matt Whiting wrote:
wrote: You're right about a barrel roll, of course, I like that you can rotate the wings through 360 degrees and maintain 1 G. You could also, I think, start the 'roll' with an upward velocity component of 320 feet a second and end it level, but hardly at the same altitude (you'd be 1600 feet higher). An even more interesting question would be, is there an airplane that can fly this flight path? I think it would take massive control surfaces to be able to pull a G with the yoke. I'm not an aerobatic pilot, but pulling 1G with the elevator isn't hard on any airplane I've flown. Matt Actually Matt, all you need to do with most g meters is to "tweak" the stick with an instant of positive pitch pressure and release it. You will register over 1 g just doing that :-)) Dudley Henriques |
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wrote in message
oups.com... Jim, you don't have to do the physics for a 1 g roll. click on stanford.edu/~sigman/one_g_roll.html for a really neat analysis. Page down toward the end of sigman's article to see the actual flight paths that it takes. It's a neat read. Oh, for the nonbelievers in Newton and vector analysis and such (Mx whatever comes to mind) don't bother. Hmmmm....some of the trajectories for varying "initial roll angles" look kinda like my drawing somewhere above in this thread. Especially the ones to the left side of the graph with higher initial angles. Only I was trying to imagine a scenario where you end up straight and level rather than finishing in a high-speed dive as Siegman's model shows. I was thinking more along the lines of pulling up the nose throughout the maneuver to induce the 1g, resulting in a corkscrew dive which you would gradually flatten until the end of the roll. By pulling up the nose to create the g-force you would not have to accelerate downward to "outrun" the acceleration of gravity. Of course Siegman's model more closely approximates a barrel roll where I think I ended up with a gradually opening spiraling dive. Mine was just a thought experiment....no math involved. :-) |
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I think by chosing an initial climb rate of 320 fps (!!) you can do
this 1 G roll and end up level but 1600 feet higher, or at a lower rate , maybe 160 fps, and end up at the same altitiude as you started, but going down 160 fps. (superposiiton works!) I sure can not think of a 1 g track that would get you straight and level from a dive, unless the dive took you through the center of the earth. Hey, there's the answer. You have to go really fast so that your fall rate is compensated by the earth being a sphere. That would be pretty fast! This part of the thread belongs over in the physics newsgroup. On Jun 14, 10:34 pm, "muff528" wrote: wrote in message oups.com... Jim, you don't have to do the physics for a 1 g roll. click on stanford.edu/~sigman/one_g_roll.html for a really neat analysis. Page down toward the end of sigman's article to see the actual flight paths that it takes. It's a neat read. Oh, for the nonbelievers in Newton and vector analysis and such (Mx whatever comes to mind) don't bother. Hmmmm....some of the trajectories for varying "initial roll angles" look kinda like my drawing somewhere above in this thread. Especially the ones to the left side of the graph with higher initial angles. Only I was trying to imagine a scenario where you end up straight and level rather than finishing in a high-speed dive as Siegman's model shows. I was thinking more along the lines of pulling up the nose throughout the maneuver to induce the 1g, resulting in a corkscrew dive which you would gradually flatten until the end of the roll. By pulling up the nose to create the g-force you would not have to accelerate downward to "outrun" the acceleration of gravity. Of course Siegman's model more closely approximates a barrel roll where I think I ended up with a gradually opening spiraling dive. Mine was just a thought experiment....no math involved. :-) |
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I can't believe I took the time to do this.
If you started at abaout 18000 miles an hour (you had better be pretty high!) when you flew this path you'd end up level with the horizon. I think this is out of the range of most general avaition airplanes. The neat thing is, though, if you wanted to have a real aerobatic flight experience on a simulator, this is the one to try. Just create a craft with the ability to go that high, that fast, with thrusters than could do this thing. Why, you could pour coffee into a cup and claim to have the same effects in the simulation as a real pilot would have in the craft. |
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wrote in message
ups.com... I can't believe I took the time to do this. If you started at abaout 18000 miles an hour (you had better be pretty high!) when you flew this path you'd end up level with the horizon. It's called orbital velocity http://electronics.howstuffworks.com/satellite3.htm I think this is out of the range of most general avaition airplanes. The neat thing is, though, if you wanted to have a real aerobatic flight experience on a simulator, this is the one to try. Just create a craft with the ability to go that high, that fast, with thrusters than could do this thing. Why, you could pour coffee into a cup and claim to have the same effects in the simulation as a real pilot would have in the craft. |
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On Jun 11, 1:09 pm, Jim Logajan wrote:
Myth: It is impossible to perform a barrel roll such that the pilot feels exactly 1 gee of force perpendicular to the floor of the cockpit. (Barrel roll is defined here as the maneuver depicted by the definitions and diagrams on these website:http://en.wikipedia.org/wiki/Barrel_...arrel_roll.jpg) Fact: The aspect that I think appears to mislead people is the presence of a gravitational field and an implied requirement that the axis of the helix must remain straight and parallel with the (flat) ground. But the latter requirement can be dispensed with and still yield a recognizable helical flight path - and that is enough to make a 1 gee barrel roll possible. The "trick" is accomplished by superimposing two equations of motion: (1) Start with a "zero gee" parabolic trajectory. So basically the plane travels laterally over the ground while first traveling up (and then down) such that the pilot would feel weightless absent any other motions. The arc is a classic parabola. (2) Superimpose by vector addition the centrifugal force of the plane "flying" a circle around (and along) the moving center established by the parabolic trajectory in (1). (3) Set the radius and angular speed of the circle in (2) to yield one gee equivalent force and rotate plane's attitude to keep the centrifugal force vector perpendicular to the floor. End of procedure. A reasonable nit pick is that the axis of the helix of the barrel roll doesn't remain "straight and level." But none of the definitions explicitly state that requirement. And in any case, it is possible to end the 1 G barrel roll at the same altitude at which it began. So there. :-) (If there is a demand (and I can find more time) I can work out and post the complete set of equations of motion.) The answer to your question as you ask it is no. You can not perform a "Barrel roll" and maintain 1 G. We all have 1 G pressing on us as we are sitting at our desks, or flying straight and level in an airplane. To perform a barrel roll, you pick a point 20 degrees off heading (usually to the left in aircraft with US engines). You then must execute the beginings of a loop by applying back pressure on the stick. You can not do this without adding additional G forces. You should be at 90 degrees bank when you are just over the point you selected 20 degrees off the origional heading. As you continue the roll, you will be at a point 40 degrees off the origional heading when you have completed 180 degrees of roll and your wings should be level with the horizion in the inverted position. As you continue the roll the nose of the aircraft will be 20 degrees below the horizion and at a 90 degree bank when you are back at the point 20 degrees off the origional heading. You now continue the last quarter of the roll while "pulling" to wings level - again you can not do this without adding G. I have done thousands of barrel rolls - and have done them with open bottles of water on the dash - same principle as swinging a bucket of water over your head and not spilling any. As long as you keep positive "G" (not gee) force on the plane - the water will not spill - let it go negative and you will have a mess. If the question you are asking is can this maneuver be done by adding 1 additional G unit (now you would be at 2 G's) the answer is you could rotate around and probably not spill the water, but you would not execute what is considered a "Barrel Roll" - it would be more of a sloppy aileron roll where you end up lowing altitude from your origional position. A "slow roll" is one where the aircraft follows a straight line and if you are doing these on a horizontal line you will not keep "positive" G's on you and the aircraft. |
#10
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SS2MO wrote
As you continue the roll, you will be at a point 40 degrees off the origional heading when you have completed 180 degrees of roll and your wings should be level with the horizion in the inverted position. How about 90 degrees off the original heading when inverted? Bob Moore |
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