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#61
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![]() "Darkwing" theducksmail"AT"yahoo.com wrote in message ... Man you are a dick. This has NOT been adequately explained or there would be no question about it. If the plane is not moving on the treadmill but rather keeping up with the speed that the treadmill is moving (yes planes DO have throttle controls) the thing is going to takeoff with no air moving over the wings? NO WAY. Maybe, in your infinite wisdom, you can explain to me why the treadmill is moving. Eh? |
#62
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Ray wrote:
Looks like airplane treadmill problem, regularly a spark for flame wars on R.A.P., has made it into the mainstream. http://pogue.blogs.nytimes.com/ Let the arguing begin! - Ray Yes, the airplane will take off. The thrust of the engine is against the AIR. NOT the treadmill. There are two real life situations analogous to this: 1) Will an airplane on an essentially frictionless surface (say, wet ice) take off? 2) Will a sea plane take off upriver in a current equal to it's take-off speed (this one is a cheat, since it involves drag not involved in the original situation, but should be a good "fire starter" for further discussion). Rip |
#63
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How is that possible if the wings are stationary? Are you saying the thing
will take off due to the pure power setting to keep up at 25mph (or whatever), nothing to do with the wings? What we're saying is that the wings aren't stationary. The airplane moves (and accelerates) forward, just as if it was on a normal runway. The speed of the airplane relative to the treadmill belt doesn't matter. Let us pretend we fly a plane over the treadmill at 80mph, and run the treadmill belt at 80mph the other direction. Now, if the airplane touches down, the wheels are going to be spinning really fast, but the airplane just keeps moving along at 80mph relative _to_the_ground_. It certainly doesn't slam to a stop because 80-80=0. Relative to the treadmill belt, it's doing 160. Now let's do the opposite. Let's run the treadmill in the same direction that the airplane is going. Now, when our airplane touches down, the wheels don't turn at all--and yet the airplane is still moving along at 80, relative to the ground. Google for videos of planes landing on top of moving cars. And, if you watch this (http://videos.streetfire.net/player....D-D6BA1A43A06B) video, you'll see that, if you have a rolling object powered by an independent (ie, non-surface-friction) power source, it will move at the same speed relative to the earth regardless of the motion of the surface on which it is placed. Watch how the skateboard starts to move forward, then the cloth/paper/whatever it is is pulled out from underneath. The skateboard doesn't even slow down. |
#64
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![]() "Peter Dohm" wrote It is really depressing that so many in a group of this type [seem to] have been taken in. Think of it this way. This was a well worn thread a while back. Most all of the "not able to fly" believers were convinced, over time. The ones that know the answer, right off, represented the more intelligent of the group. Now, there have been many people that came in from other cess pools, following MX. They are non-believers. Many of the intelligent ilk that understood, right off, have left, disgusted from MX ability to troll and remain, and the many members allowing him to remain with a foothold. There you have it. MX is by large part responsible for so many responses of the non-thinking crowd. I see no other possible interpretation. -- Jim in NC |
#65
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In article ,
"Darkwing" theducksmail"AT"yahoo.com wrote: Okay Mr. Cynical, I sent an email off to the Mythbusters explaining this whole thing and a link to the Google Groups thread so we'll see if they pick it up and show it on the program. doubt it. It's not a myth. -- Bob Noel Looking for a sig the lawyers will hate |
#66
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"Darkwing" theducksmail"AT"yahoo.com wrote in message
This has NOT been adequately explained or there would be no question about it. If the plane is not moving on the treadmill but rather keeping up with the speed that the treadmill is moving (yes planes DO have throttle controls) the thing is going to takeoff with no air moving over the wings? NO WAY. Assuming you're a pilot, I don't understand why you think no air would be moving over the wings, but I'll give this one good "college try"... First, the question posed in the link by the OP of this thread is an incorrect variation of the original. The original problem asks: "A plane is standing on a giant treadmill. The plane moves in one direction, while the treadmill moves in the opposite direction and at the same speed as the plane. Can the plane take off?" As has been explained, placing a car on the question's treadmill would result in a stationary vehicle relative to the observer standing beside the treadmill. The reason is the car derives its propulsion through the wheels sitting on the treadmill and the speed of the car is measured by how fast the wheels are turning. The faster the wheels turn, the "faster" the car moves. However, this is only relative to the treadmill belt. To the observer standing beside the treadmill, the car is motionless. If the driver placed his hand out the window, he would feel no wind even though his "speed" as indicated by the speedometer may be 100 miles per hour. This is very similar to your example of running on the treadmill. You did not feel a relative wind in your face because you were stationary relative to the observer standing beside the treadmill. The reason you were stationary is you generate your propulsion by moving your feet against the ground (or belt, in this case) and the belt is moving in the opposite direction and same speed of your "travel". Like the car, your speed is measured by how fast your feet move from front to rear and they match the speed of the belt to cancel out each other. Now, replace the car and runner with an airplane. The airplane derives its propulsion from its engine pushing air from front to back. None of this energy is sent to the wheels to propel the airplane. The speed of the airplane is measured by the flow of air past the airplane, not the turning of its wheels. As the airplane's engine spools up to takeoff power, air is forced from front to rear and the plane moves forward regardless how fast its wheels are turning. The observer standing beside the treadmill would notice the treadmill speed up, the airplane's wheels turn twice as fast as normal, and the airplane move forward (not stationary). Speed is relative and the key here is the means of propulsion. The airplane's speed is measured by how fast the air is moving past it, not by how fast its wheels are turning or how fast the ground is flashing by. None of the airplane engine's energy is transmitted to the wheels to generate speed. All of the airplane's propulsion is derived from moving air (otherwise it would never stay in the air after takeoff). Since the treadmill has very little effect on the air (and what little effect it does have actually helps the airplane generate more lift), the airplane will indeed takeoff in the same distance it normally would use without the treadmill. However, the airplane wheels would be turning at twice their normal speed at the time of takeoff. Try this experiment: Take a toy car and attach it to a string. Tie the other end of the string to a small spring scale. Place the car on the treadmill belt and hold the scale in front of the car while you turn on the treadmill. Observe nearly zero (essentially 1G) force being exerted on the string/scale. Speed up the treadmill (for simplicity, let's say you set it to a constant 10mph) and you'll observe no significant difference in force exerted on the string (the only additional force is the friction of the car's axles). Now gently pull the string/scale forward. As long as you maintain a 1G force on the string, the car will continue to accelerate. Now, to the observer standing beside the treadmill, was the car stationary or moving forward? It's speed was certainly not zero as the car most definitely moved from rear to front of the belt. What was the speed of the car relative to the "driver" sitting inside the toy? The wheels would be turning faster than 10mph. If the "driver" were to put his hand out the window, how fast would the air be moving? Much slower than his wheels would say he's moving, but faster than the driver I mentioned at the beginning of this post. Replace the toy with the mythical airplane above, replace your arm with the airplane's engine (and propeller, if appropriate), then replace the string with the airplane engine mounts. You should now be able to visualize why the airplane sitting on that giant treadmill would most definitely takeoff. If not, I wish you good luck and safe flight. You'll need it. ![]() -- John T http://sage1solutions.com/blogs/TknoFlyer Reduce spam. Use Sender Policy Framework: http://openspf.org ____________________ |
#67
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"Richard Riley" wrote in message
... You have a wind tunnel without a ceiling? Cool. If you cannot be bothered to be clear about what you mean when you write "is a real pain", I cannot be bothered to restrict my understanding of such an ambiguous statement to such mundane issues as a ceiling. An airplane in a wind tunnel can climb just as well as it can accomplish any other action an airplane might do. Within the confines of the wind tunnel, the airplane can behave completely normally, relative to anything an airplane can do. Climbing or otherwise. You have a treadmill that's a couple of thousand feet long? Cool. The question specifically posits a treadmill long enough to serve as a runway. In any case, you made no indication that your objection was based on the length of the treadmill. Either way, you are missing the point. Pete |
#68
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"Richard Riley" wrote in message
... On Tue, 12 Dec 2006 16:38:30 -0500, "mike regish" wrote: Come on. You can't be serious. mike "Richard Riley" wrote in message .. . And, just to keep it on topic, the only planes that could take off from a treadmill are the Osprey and the Harrier. Unless you have a treadmill that's a few hundred to several thousand feet long, yes. Yes we do--according the the original problem statement, the treadmill is as long and wide as the runway ordinarily used by the aircraft. Further, despite attempts at humor by me and others, no unusual obstacles were added to the end of the magic moving runway; nor was any anomaly present in the atmosphere relative to the surrounding terrain and/or the aircraft. Therefore, the giant magic treadmill was the ONLY anomaly on the magic airport--and it was trivial since the wheels did not propel the aircraft. Peter |
#69
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![]() "John T" wrote in message ... "Darkwing" theducksmail"AT"yahoo.com wrote in message This has NOT been adequately explained or there would be no question about it. If the plane is not moving on the treadmill but rather keeping up with the speed that the treadmill is moving (yes planes DO have throttle controls) the thing is going to takeoff with no air moving over the wings? NO WAY. Assuming you're a pilot, I don't understand why you think no air would be moving over the wings, but I'll give this one good "college try"... Yes I am a pilot. First, the question posed in the link by the OP of this thread is an incorrect variation of the original. The original problem asks: "A plane is standing on a giant treadmill. The plane moves in one direction, while the treadmill moves in the opposite direction and at the same speed as the plane. Can the plane take off?" As has been explained, placing a car on the question's treadmill would result in a stationary vehicle relative to the observer standing beside the treadmill. The reason is the car derives its propulsion through the wheels sitting on the treadmill and the speed of the car is measured by how fast the wheels are turning. The faster the wheels turn, the "faster" the car moves. However, this is only relative to the treadmill belt. To the observer standing beside the treadmill, the car is motionless. If the driver placed his hand out the window, he would feel no wind even though his "speed" as indicated by the speedometer may be 100 miles per hour. This is very similar to your example of running on the treadmill. You did not feel a relative wind in your face because you were stationary relative to the observer standing beside the treadmill. The reason you were stationary is you generate your propulsion by moving your feet against the ground (or belt, in this case) and the belt is moving in the opposite direction and same speed of your "travel". Like the car, your speed is measured by how fast your feet move from front to rear and they match the speed of the belt to cancel out each other. Now, replace the car and runner with an airplane. The airplane derives its propulsion from its engine pushing air from front to back. None of this energy is sent to the wheels to propel the airplane. The speed of the airplane is measured by the flow of air past the airplane, not the turning of its wheels. As the airplane's engine spools up to takeoff power, air is forced from front to rear and the plane moves forward regardless how fast its wheels are turning. The observer standing beside the treadmill would notice the treadmill speed up, the airplane's wheels turn twice as fast as normal, and the airplane move forward (not stationary). Speed is relative and the key here is the means of propulsion. The airplane's speed is measured by how fast the air is moving past it, not by how fast its wheels are turning or how fast the ground is flashing by. None of the airplane engine's energy is transmitted to the wheels to generate speed. All of the airplane's propulsion is derived from moving air (otherwise it would never stay in the air after takeoff). Since the treadmill has very little effect on the air (and what little effect it does have actually helps the airplane generate more lift), the airplane will indeed takeoff in the same distance it normally would use without the treadmill. However, the airplane wheels would be turning at twice their normal speed at the time of takeoff. Try this experiment: Take a toy car and attach it to a string. Tie the other end of the string to a small spring scale. Place the car on the treadmill belt and hold the scale in front of the car while you turn on the treadmill. Observe nearly zero (essentially 1G) force being exerted on the string/scale. Speed up the treadmill (for simplicity, let's say you set it to a constant 10mph) and you'll observe no significant difference in force exerted on the string (the only additional force is the friction of the car's axles). Now gently pull the string/scale forward. As long as you maintain a 1G force on the string, the car will continue to accelerate. Now, to the observer standing beside the treadmill, was the car stationary or moving forward? It's speed was certainly not zero as the car most definitely moved from rear to front of the belt. What was the speed of the car relative to the "driver" sitting inside the toy? The wheels would be turning faster than 10mph. If the "driver" were to put his hand out the window, how fast would the air be moving? Much slower than his wheels would say he's moving, but faster than the driver I mentioned at the beginning of this post. Replace the toy with the mythical airplane above, replace your arm with the airplane's engine (and propeller, if appropriate), then replace the string with the airplane engine mounts. You should now be able to visualize why the airplane sitting on that giant treadmill would most definitely takeoff. If not, I wish you good luck and safe flight. You'll need it. ![]() -- John T Thank you for your reply. Here is my .02, it would seem that the plane never actually moves in respect to the observer no matter how fast the treadmill moves, the plane will just take off like it is hovering and then slowly accelerate away? I guess I'll have to set this up and try it, I do have a few RC planes laying around and I have a treadmill so I guess I'll know one way or another, unless Mythbusters beats me to the punch. ------------------------------------------------------- DW |
#70
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"Peter Duniho" wrote in message
... "T o d d P a t t i s t" wrote in message news ![]() [...] Agreed, further interpretation is required, although I think the most reasonable interpretation is pretty clear But that's my point. Just as a "reasonable interpretation" is required, one can just as easily assert that a MORE reasonable interpretation would be to assume the question means to discuss a scenario that is at least theoretically possibly to reproduce with existing technology. The question is ambiguous no matter how one looks at it. How can anyone assert that it makes more sense to interpret it in a way that creates a physically impossible situation than to interpret in a way that can at least in theory be tested experimentally? Pete Yup. The question can be interpreted in a couple of different ways. This is what has created the multi-faceted debate. We are not just debating whether the plane will fly given a single scenario. We are arguing about the scenario itself. Stupid, really. I mean, the arguing is stupid. I'm all for discussing alternate scenarios to gain enlightenment (which I got the last round - no new information this time). I happen to believe that the point of the scenario is to illustrate the independence (within limits of friction) of the motion of the plane from its connection to the ground. I think that the alternate scenarios are interesting and have their own merit. However, there are those that clearly do not get the independent nuance of airmotive thrust (e.g. Darkwing). ------------------------------- Travis Lake N3094P PWK |
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