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Texas Parasol Plans...
Cla
Bearing properties are used when designing mechanically fastened joints. The purpose of a bearing test is to determine the the deformation of a hole as a function of the applied bearing stress. The test specimen is basically a piece of sheet or plate with a carefully prepared hole some standard distance from the edge. Edge-to-hole diameter ratios of 1.5 and 2.0 are common. A hardened pin is inserted through the hole and an AXIAL load applied to the specimen and the pin. The bearing stress is computed by dividing the load applied to the pin, which bears against the edge of the hole, by the bearing area (the product of the pin diameter and the sheet or plate thickness). Different axis and on edge rather than in tension or compression. The flat surface described by the hole in the part as it passes through the thickness of the tube or plate of the hole. The stress is spread through the material differently. Curtis S. And I am not an engineer either, I make rocket motors, and need this information constantly. clare at snyder.on.ca wrote: On Mon, 27 Feb 2006 15:14:24 -0500, Curtis Scholl wrote: Cla Looking at the calculations for the spar, spar.pdf I do not see your interpretation. The 67000 psi value is Bearing Ultimate, not tensile. A MATWEB lookup is in order: 6061-T6 Tensile ultimate: 45000 Tensile yield : 39000 Bearing ultimate: 88000 Bearing Yield : 56000 The values presented in the spar calculation are correct, and the bearing ultimate of 67000 is below spec. Thjat may well be true, but is "bearing strength" the proper charachteristic of the material to be used in this calculation? As I said - not an engineer - just asking. Please explain for the rest of us how the bearing ultimate and / or yeild values impact the calculation, vs tensile. *** Free account sponsored by SecureIX.com *** *** Encrypt your Internet usage with a free VPN account from http://www.SecureIX.com *** |
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