forgotten trig for climb angle...

I remember that sin c = excess thrust/weight

What step do I then do to convert sin c into degrees above the horizon?

TIA

You simply want to know what angle has that sine. arc sin (c) would be
the function on the calculator you're looking for.
On Jan 28, 5:54 pm, "xerj" wrote:
I remember that sin c = excess thrust/weight

What step do I then do to convert sin c into degrees above the horizon?

TIA

Ahhh that's right!

Thanks.

"Tony" wrote in message
oups.com...

You simply want to know what angle has that sine. arc sin (c) would be
the function on the calculator you're looking for.
On Jan 28, 5:54 pm, "xerj" wrote:
I remember that sin c = excess thrust/weight

What step do I then do to convert sin c into degrees above the horizon?

TIA

You can make it a little easier on yourself, for small angles just
multiply the sine by 57. For example, a 10 degree climb angle is
pretty steep. sin(10) is 0.1736. The approximation I mentioned would
return 9.9 degrees (that's because for small angles sin(angle) is
pretty much equal to tan(angle) and to the angle itself if measured in
radians.




j" wrote:
Ahhh that's right!

Thanks.

"Tony" wrote in ooglegroups.com...





You simply want to know what angle has that sine. arc sin (c) would be
the function on the calculator you're looking for.
On Jan 28, 5:54 pm, "xerj" wrote:
I remember that sin c = excess thrust/weight

What step do I then do to convert sin c into degrees above the horizon?

TIA- Hide quoted text -- Show quoted text -

"Tony" wrote in message
ups.com

You can make it a little easier on yourself, for small angles just
multiply the sine by 57. For example, a 10 degree climb angle is
pretty steep. sin(10) is 0.1736. The approximation I mentioned would
return 9.9 degrees (that's because for small angles sin(angle) is
pretty much equal to tan(angle) and to the angle itself if measured in
radians.

Cockpit math is hard enough. Cockpit trigonometry? Are you kdding??

--
John T
http://sage1solutions.com/blogs/TknoFlyer
Reduce spam. Use Sender Policy Framework: http://openspf.org
____________________

Sorry, I lost my head!

And my wife balances the checkbook. Go figure. (pun intended).

On Jan 29, 7:33 am, "John T" wrote:
"Tony" wrote in oglegroups.com



You can make it a little easier on yourself, for small angles just
multiply the sine by 57. For example, a 10 degree climb angle is
pretty steep. sin(10) is 0.1736. The approximation I mentioned would
return 9.9 degrees (that's because for small angles sin(angle) is
pretty much equal to tan(angle) and to the angle itself if measured in
radians.Cockpit math is hard enough. Cockpit trigonometry? Are you kdding??

--
John Thttp://sage1solutions.com/blogs/TknoFlyer
Reduce spam. Use Sender Policy Framework:http://openspf.org
____________________