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#71
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#72
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Whoops I was looking at the wing tables only, the 747 wing can fly
O.K. at a 650K combined vehicle weight (piggyback) at FL410 1g but the 67,000 lbs thrust class stock -200F engines may or may not get us up to FL410. I don't seem to have a pure climb capability chart, since my tabular tables assume you will pull climb power and then throttle back to a Cruise thrust limit at ISA+10. You can *maintain* only 38,000ft at that weight throttled back to Cruise thrust. And that's not what we're planning on. I'm planning on MCT at 100ft/min until we crawl up as high as she will go and then going to the absolute limit in thrust up there which is G/A EPR for five minutes. However, I'm not considering the drag of this attached space vehicle! Better get partner Bill Gates to float us a loan for four C-90 class engines! pac "little engines that could" plyer |
#73
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"pacplyer" wrote in message m... That's why enjoy discussing experimental space solutions on an un-moderated homebuilt aircraft NG like RAH. I don't think a moderator could be well versed enough on all the disparate backgrounds necessary to plan something like this out. He just couldn't make good decisions on who to post and who to block. Take Tim for example. This guy has actually taken a TRUCK and surfed behind it, in tow, with his hang gliders! You just can't buy better real world experience than that. Don't make more out of that than it is. Truck towing is a very popular way to launch hang gliders. LOTS of hang glider pilots launch that way. After twenty years, it ain't exactly bleeding edge technology. So what do we have now? The OrbitOne vehicle on top of the tow aircraft courtesy Jim Morgan's good idea. It just has to clear the 74 vertical stab at release; but the Space Shuttle "Enterprise" test vehicle proved that can be done. I like Tim Ward's two wing component idea: an SS1 type "re-entry" inner wing with a 100ft swingable detatchable glider wing on each tip to be deployed after detach from the mother ship No, viewed from the front, the "joined wing" looks like a big diamond. It attaches under the nose and at the top of the rudder. In the dismount, the front wing pivots down, away from the orbiter, around the rear attach point -- which can just slide out backwards. There just may be enough brain power on this NG to put together a computer model! Here's the 680k t/o weight 747 tow-ship vertical profile as I see it so far: V2 + 10 to 1000ft agl, clean up accel to 3000ft agl, call for climb power, accel to 250, IAS hold to 10,000msl, alt hold, accel to best rate of climb about 320kts is a good guess unless that exceeds glider/OrbitOne "piggyback stability" speeds, then continue climb up to 24,500 ft, switch over to Mach .82 climb and hold that with Mach Hold, and call for MCT (max continuous thrust) power when rate of climb drops off, then call for G/A (go around) thrust (five minute limit) when rate of climb drops off, and level off at FL410 (since an [up to] 250,000 lb space vehicle is now riding on our back we can't make FL450.) Note we will be at about a 650,000 joined vehicle weight upon reaching FL410 in this senerio. Detach OrbitOne with coordinated push over maneuver and descend 747 tow aircraft back down to FL350 accelerating to MMO .92 mach in the descent (pull back to MCT power.) No, once you've released OrbitOne, rather than pull power, you add line tension to slow down. Remember the 747 engines are our booster. We want them running as at high a power as we can all the stinkin' time. We recover some of the 747's potential energy that way. Pay out cable and let OrbitOne/glider ascend as high as possible (75,000-100,000 ft.) Level towship at FL350, call for G/A thrust and enter 45 degree bank, bracing for possible cable break and resultant pitch down and overspeed. When Colonauts release the cable (coordinated,) slam to idle 747 power, deploy full speedbrakes, level wings, pull up with authority, and recover from resultant mach buffet. Ya know, I hate to say it guys: but this Rube Goldberg type solution may just be nothing short of brilliant. It IS, as described above, from a preliminary perspective, all just barely within the capabilities of a stock B747-200F with JT9D-Q or -70A engines and more importantly: does not require superior ****ing airmanship skills on the part of the tow ship PIC. We need to further explore several tow tether candidates like Tim's "Vetron" rope. 1: We need to calc the tension involved using Kevin Horton's 3 to 1 speed slingshot target (77,000ft radius.) 2. We need to calculate a drag number for this 24km tether at a selected average thickness. That's Vectran. Bill Daniel's suggestion of carbon nanotube fiber would be great -- if it existed. Well, what you are waiting for? An engraved invitation? Get to work and make some engineering decisions! I'm just a towship driver. I don't know how to calculate the tether load we're going to experience in the 45 degree bank. With the payout winch, until you run out of line, the tension in the line is whatever the payout winch is set for. Drag on the line: not only at the selected thickness, but there's a big altitude difference as well. Fortunately, the thick end of the line is up where the air is thinner. When you're doing the turning maneuver, the speed continuously varies from one end to the It's non-linear with line length because of the caternary in the tow line. What happens if the tow line goes supersonic? I suspect the drag goes way up because of the shock wave, but are there instabilities as a result? pacplyer Tim Ward |
#74
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"pacplyer" wrote One of the things I didn't want to bring up was wake turbulence on take off; since I knew it would probably kill the project. Even heavy jets wait at least two minutes before following the jumbo on t/o; to give the house-sized wake vortices time to roll off the runway. Otherwise you wind up on your head if you're light, and temporarily out of control even if you're a 727. Most likely not a show stopper, since most of the energy is out at the tips, which will be behind the C.G. Our orbiter will be ahead of the main turdulance. Plus the fact that the vortcies descend as the are formed and linger. -- Jim in NC --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.711 / Virus Database: 467 - Release Date: 6/26/2004 |
#75
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"Morgans" wrote in message ...
"pacplyer" wrote One of the things I didn't want to bring up was wake turbulence on take off; since I knew it would probably kill the project. Even heavy jets wait at least two minutes before following the jumbo on t/o; to give the house-sized wake vortices time to roll off the runway. Otherwise you wind up on your head if you're light, and temporarily out of control even if you're a 727. Most likely not a show stopper, since most of the energy is out at the tips, which will be behind the C.G. Our orbiter will be ahead of the main turdulance. Plus the fact that the vortcies descend as the are formed and linger. I'm speaking of tow ops on the runway. I wonder where a 250,000 lb vehicle would break ground in tow behind the 747? Engines of that size alone put out bad turb 1500 feet behind them. How far back would it be behind the towship at brake release? And if you have a ten knot or so crosswind it can blow a wing-tip vorticie back up onto the runway centerline and ruin your whole day. Ten knot crosswinds are 80% of Mojave days. Nasa and SS1 avoided this with the piggyback schemes. Maybe also the vehicle on top can be designed to provide part of the combined lift liberating more power for getting to target altitude. Data exists and is pubic about NASA's 747 carrier aircraft; so flight test development cost might be low. I like this roofmount/payout on cable idea better. Is the payout cable tension adjustable in flight? At vehicle split you'd want the payout cable resistance to be low for a few seconds right? So you'd get a positive clearance on the 74 vert stab? pac |
#76
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"pacplyer" wrote I'm speaking of tow ops on the runway. ***I see. You were talking about before we put it up top. I wonder where a 250,000 lb vehicle would break ground in tow behind the 747? ***Not soon enough! g Maybe also the vehicle on top can be designed to provide part of the combined lift liberating more power for getting to target altitude. ***Yes. Otherwise you could get a negatibe AOA, and have a "Voyager takeoff wingtip droop", which most people think is a bad thing. I still cant believe Burt blew it on that one. Oh well, no harm, no foul. Gotta be careful, not to get too much AOA, or the high indicated airspeed down low, could pull those long wings right off. We had better make the mount to have an adjustable AOA, so we can crank in some more AOA when we start to get up high, to help out more in getting up there. I like that. Another thing that would do is reduce development time; getting the AOA just right. Another good thing that would do is get the orbiter to pop off the roof quick, to get away from boundary flow, and clear the vertical stab. Is the payout cable tension adjustable in flight? At vehicle split you'd want the payout cable resistance to be low for a few seconds right? So you'd get a positive clearance on the 74 vert stab? ***Yes. More tension would be like more thrust, to get higher AOA right off, to get that high angle of climb. Also, once we get lots of cable out, we want to slow the cable, and stop it, so we can crack the whip with the cable locked. The thing that has me most concerned is cable aero drag. I think we better make that cable streamlined, and *real* thin, or drag could spell an end, right off. -- Jim in NC --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.714 / Virus Database: 470 - Release Date: 7/2/2004 |
#77
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"Tim Ward" wrote in message snips throughout ...
No, viewed from the front, the "joined wing" looks like a big diamond. It attaches under the nose and at the top of the rudder. In the dismount, the front wing pivots down, away from the orbiter, around the rear attach point -- which can just slide out backwards. Good. A single piece so that you can't get asymmetrical detachment. How would it be recovered I wonder? Remote fly down? probably it would flutter end over end until a chute deployed? Sorry but unlike gov ops this mission has to be profitable! Here's the 680k t/o weight 747 tow-ship vertical profile as I see it so far: V2 + 10 to 1000ft agl, clean up accel to 3000ft agl, call for climb power, accel to 250, IAS hold to 10,000msl, alt hold, accel to best rate of climb about 320kts is a good guess unless that exceeds glider/OrbitOne "piggyback stability" speeds, then continue climb up to 24,500 ft, switch over to Mach .82 climb and hold that with Mach Hold, and call for MCT (max continuous thrust) power when rate of climb drops off, then call for G/A (go around) thrust (five minute limit) when rate of climb drops off, and level off at FL410 (since an [up to] 250,000 lb space vehicle is now riding on our back we can't make FL450.) Note we will be at about a 650,000 joined vehicle weight upon reaching FL410 in this senerio. Detach OrbitOne with coordinated push over maneuver and descend 747 tow aircraft back down to FL350 accelerating to MMO .92 mach in the descent (pull back to MCT power.) No, once you've released OrbitOne, rather than pull power, you add line tension to slow down. Remember the 747 engines are our booster. We want them running as at high a power as we can all the stinkin' time. We recover some of the 747's potential energy that way. Hopefully we won't be slowing down! :-) Once you get the whale on the step you'd like to leave her there. It's damn hard to recover lost cruise speed below .84 mach when you're heavy up there. That's my reason for splitting the vehicles as high as we can, and then going downhill on the payout: heading for thicker air for the bank maneuver. MCT (max continuous thrust) in the descent is almost full power (sometimes they're the same EPR (engine pressure ratio) setting. We have to throttle back a scoash to this after five minutes of Go-Around thrust (the highest setting) or else bad thermodynamics in the engine start happening. Also Blade creep is possible – a very expensive boo-boo. But I see what you're saying. When I get to MMO (Mach Max Op) of .92m, don't pull back any power, just add line tension. Thanks Tim. I didn't understand that part of the scheme. That being the case, the towship pilot needs a tether line payout tension control. I envision this to be used just like a throttle lever. The flight engineer will keep max power going all the time, while the pilot controls overspeed after split by varying the line tension with his line tension lever. Used like a throttle the same way the Shuttle guys use the bellybrake lever. Very do-able. I like it. With the payout winch, until you run out of line, the tension in the line is whatever the payout winch is set for. So you'd raise the payout winch tension up against max line tether strength just prior to the bank maneuver? Drag on the line: not only at the selected thickness, but there's a big altitude difference as well. Fortunately, the thick end of the line is up where the air is thinner. When you're doing the turning maneuver, the speed continuously varies from one end to the It's non-linear with line length because of the caternary in the tow line. Looks like this post got cut off. Could you elaborate some more on this for me? Talk more about "caternary" for me and the dynamics of this line. What happens if the tow line goes supersonic? I suspect the drag goes way up because of the shock wave, but are there instabilities as a result? Tim Ward Good question. That hadn't occured to me. There's only one man who has enough design confidence to find out: Burt da man. Well it's been a fun thread everybody. Good posts by all. pacplyer |
#78
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Morgans wrote:
The thing that has me most concerned is cable aero drag. I think we better make that cable streamlined, and *real* thin, or drag could spell an end, right off. -- Jim in NC Based on some very shakey assumptions... Looking for drag per killometer of cable.... 1) Using EAS for speed (already corrected for temperature and pressure at cruise altitude) 218 K EAS = 250 MPH 2) that makes Q = 160 (.00256 * V^2 where V in MPH) 3) RN = 7657 Million (that's for 1 KM chord - in line with slipstream) Viscosity effects predominate onthe part of thecable in trail! But I have no clue how to calculate the drag on that part... 4) For the part of the cable that is _perpendicular_ to the slipstream... Dp = Cd S Q Cd = .02 ?? for a round cross section Cable diameter guessed at 2 inches diameter S = 546 sq feet per Km of cable length Dp = 1750 pounds per Km of cable exposed perpendicular to the stream. Well? |
#79
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Richard Lamb wrote
Based on some very shakey assumptions... Looking for drag per killometer of cable.... 1) Using EAS for speed (already corrected for temperature and pressure at cruise altitude) 218 K EAS = 250 MPH 2) that makes Q = 160 (.00256 * V^2 where V in MPH) 3) RN = 7657 Million (that's for 1 KM chord - in line with slipstream) Viscosity effects predominate onthe part of thecable in trail! But I have no clue how to calculate the drag on that part... 4) For the part of the cable that is _perpendicular_ to the slipstream... Dp = Cd S Q Cd = .02 ?? for a round cross section Cable diameter guessed at 2 inches diameter S = 546 sq feet per Km of cable length Dp = 1750 pounds per Km of cable exposed perpendicular to the stream. Well? Nice formula Richard. If you don't mind I'm going to email it to my friend at Scaled tomorrow. Don't worry; it's just for grins. I spoke with him briefly last night and asked him Tim's question about the line speed when the tow plane banks and gives a 3 to 1 speed advantage to the Orbiter. He says the line going supersonic is no problem; "it just Zings" he told me. There are no stability problems with the line at Mach numbers. Edwards has lots of experience with supersonic tow lines. Just for my education, what was your source and method for calculating your Reynolds Number? What pressure altitude did you use? I'm thumbing through my old "Theory of Wing Sections" by Abbott and Von Doenhoff, but it's not making much sense to me! So if we double your drag per km number, just for ballpark "do-abiltiy" wag calcs, and call it 3500 lbs of drag per Km of cable exposed perpendicular to the stream, since it'll be semi-vertical just prior to towship 45 degree bank maneuver, that yields: 84,000lbs of drag for 24km of line. Let's see: four engines producing 67,000lbs of thrust at SL… [note: we don't know yet what it is at FL 410 but, P&W has those charts and we can guess it's pretty high since we can pull 1.71 normal climb EPR at FL410 which is only .02 off the max value on the table.] Four engines pulling 67,000lbs plus 5,000 lbs of thrust from the APU chugging out the tail (no I'm not making this up) gives us 273,000 lbs of potential pounds of thrust (minus minor alt effects) to overcome the line drag coefficient with. Now most of this is going to be used just getting the mated vehicles to 41,000 ft. But once I get that 150,000 lb OrbitOne off my back (I keep forgetting about the 100,000lbs of winch and cable so the OrbitOne wt limit is 150,000lbs), I'll have 190,000 lbs of thrust avaiable for aircraft speed control above whats required to overcome the line drag. That is, when the line's pulled out all the way 24km out the roof (84,000lbs of drag.) But at vehicle split the line will still be short so the drag from it is negligible, and I can accelerate up to .92 mach, in a shallow descent. Once I get down to FL350 (where the 747 was designed to make money,) and pay out all that heavy cable in the process (say 75,000 lbs of Vetran) I'm lighter than **** at 445,000 lbs [380k empty wt+40Kgas remaining+25k winch pallet wt] so will 84,000 lbs of line drag have me struggling to hold MMO .92? Don't know, lets go try it. Let's see: 100million a launch, or $100,000 a launch? (10,000 per hr for 747, plus OrbitOne prep and support costs guessed at 90K.) Look out NASA, this SpaceSlingShot thing is worth exploring further since on paper it's 100 times cheaper to launch payloads and people into orbit than the shuttle. ;-) Cheers, pac "beautiful dreamer" plyer stay tuned for more wild numbers |
#80
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pacplyer wrote:
Richard Lamb wrote Based on some very shakey assumptions... Looking for drag per killometer of cable.... 1) Using EAS for speed (already corrected for temperature and pressure at cruise altitude) 218 K EAS = 250 MPH 2) that makes Q = 160 (.00256 * V^2 where V in MPH) 3) RN = 7657 Million (that's for 1 KM chord - in line with slipstream) Viscosity effects predominate onthe part of thecable in trail! But I have no clue how to calculate the drag on that part... 4) For the part of the cable that is _perpendicular_ to the slipstream... Dp = Cd S Q Cd = .02 ?? for a round cross section Cable diameter guessed at 2 inches diameter S = 546 sq feet per Km of cable length Dp = 1750 pounds per Km of cable exposed perpendicular to the stream. Well? Nice formula Richard. If you don't mind I'm going to email it to my friend at Scaled tomorrow. Don't worry; it's just for grins. I spoke with him briefly last night and asked him Tim's question about the line speed when the tow plane banks and gives a 3 to 1 speed advantage to the Orbiter. He says the line going supersonic is no problem; "it just Zings" he told me. There are no stability problems with the line at Mach numbers. Edwards has lots of experience with supersonic tow lines. Just for my education, what was your source and method for calculating your Reynolds Number? What pressure altitude did you use? I'm thumbing through my old "Theory of Wing Sections" by Abbott and Von Doenhoff, but it's not making much sense to me! So if we double your drag per km number, just for ballpark "do-abiltiy" wag calcs, and call it 3500 lbs of drag per Km of cable exposed perpendicular to the stream, since it'll be semi-vertical just prior to towship 45 degree bank maneuver, that yields: 84,000lbs of drag for 24km of line. Let's see: four engines producing 67,000lbs of thrust at SL… [note: we don't know yet what it is at FL 410 but, P&W has those charts and we can guess it's pretty high since we can pull 1.71 normal climb EPR at FL410 which is only .02 off the max value on the table.] Four engines pulling 67,000lbs plus 5,000 lbs of thrust from the APU chugging out the tail (no I'm not making this up) gives us 273,000 lbs of potential pounds of thrust (minus minor alt effects) to overcome the line drag coefficient with. Now most of this is going to be used just getting the mated vehicles to 41,000 ft. But once I get that 150,000 lb OrbitOne off my back (I keep forgetting about the 100,000lbs of winch and cable so the OrbitOne wt limit is 150,000lbs), I'll have 190,000 lbs of thrust avaiable for aircraft speed control above whats required to overcome the line drag. That is, when the line's pulled out all the way 24km out the roof (84,000lbs of drag.) But at vehicle split the line will still be short so the drag from it is negligible, and I can accelerate up to .92 mach, in a shallow descent. Once I get down to FL350 (where the 747 was designed to make money,) and pay out all that heavy cable in the process (say 75,000 lbs of Vetran) I'm lighter than **** at 445,000 lbs [380k empty wt+40Kgas remaining+25k winch pallet wt] so will 84,000 lbs of line drag have me struggling to hold MMO .92? Don't know, lets go try it. Let's see: 100million a launch, or $100,000 a launch? (10,000 per hr for 747, plus OrbitOne prep and support costs guessed at 90K.) Look out NASA, this SpaceSlingShot thing is worth exploring further since on paper it's 100 times cheaper to launch payloads and people into orbit than the shuttle. ;-) Cheers, pac "beautiful dreamer" plyer stay tuned for more wild numbers Oh great! There goes my chance at getting hired! One thing I already know about is that the Cd increases (a lot) in the transonic range, and again (even more) for supersonic. Problem is, the drag bill gets paid before anything else does. So it's entirely likely that the 'zing' is gonna 'fizzle'... Still, it will be interesting to see what the cool guys say. (a little kissing up might keep them from laughing so hard?) Richard |
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