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#1
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David Rind wrote:
Not answering your actual question about the clearance, but for what it's worth, I would not have tried to climb out at Vx. You have no hope of outclimbing a jet, It's not that far off -- I think (but am not certain) that a fully-loaded DC-9 has a best climb angle of around 650 ft/nm, while a small single-engine plane will manage something like 400-600 ft/nm at Vx depending on horsepower and load. Of course, the DC-9 has a much better climb *rate*, but that's not the concern here (also, the DC-9 is designed for short fields; other transport jets may have worse climb angles). More importantly, a Vx climb will probably put you a couple of hundred feet up and another 30 seconds behind by the time you arrive above the point where the DC-9 lifted off -- that gives you lots of room to make a turn before you intersect its path. If you took off at a higher speed, you'd have less space for your turn because your climb angle would be lower (even though the rate was higher). Even if you stay straight ahead, at VX you probably won't intersect the DC-9's climb path until the vortices are well-dissipated. A slow forward speed is your friend in this situation, either way. All the best, David |
#2
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David Megginson wrote:
David Rind wrote: Not answering your actual question about the clearance, but for what it's worth, I would not have tried to climb out at Vx. You have no hope of outclimbing a jet, It's not that far off -- I think (but am not certain) that a fully-loaded DC-9 has a best climb angle of around 650 ft/nm, while a small single-engine plane will manage something like 400-600 ft/nm at Vx depending on horsepower and load. Of course, the DC-9 has a much better climb *rate*, but that's not the concern here (also, the DC-9 is designed for short fields; other transport jets may have worse climb angles). More importantly, a Vx climb will probably put you a couple of hundred feet up and another 30 seconds behind by the time you arrive above the point where the DC-9 lifted off -- that gives you lots of room to make a turn before you intersect its path. If you took off at a higher speed, you'd have less space for your turn because your climb angle would be lower (even though the rate was higher). Even if you stay straight ahead, at VX you probably won't intersect the DC-9's climb path until the vortices are well-dissipated. A slow forward speed is your friend in this situation, either way. You are clearly right about this -- I was thinking in terms of rate of climb, not angle of climb. That said, I would still be more interested in making an early turn than in trying to climb quickly and would always ask for an early turnout in this situation.... -- David Rind |
#3
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David Rind wrote:
You are clearly right about this Thank you for the gracious reply. -- I was thinking in terms of rate of climb, not angle of climb. That said, I would still be more interested in making an early turn than in trying to climb quickly and would always ask for an early turnout in this situation.... In this particular case (taking off right after a jet), at Vx you will reach turning altitude in less distance and more time, both of which work in your favour: - less distance means that you are at a safe turning altitude further away from the point where your climb path would intersect the jet's climb path - more time means that the the jet's wake vortices have had more opportunity to dissipate by the time you turn. Or, to put it the other way, if you climb at Vy you will arrive closer to the jet's climb path, sooner, before you reach a point when you can turn. On the other hand, if there were a jet waiting to take off behind me and I wanted to get out of the way as soon as possible (i.e. ATC says "right turn to heading XXX as soon as safely able"), then Vy is the better choice, since I want to get to turning altitude in the least time. All the best, David |
#4
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David Rind wrote in message ...
David Megginson wrote: David Rind wrote: Not answering your actual question about the clearance, but for what it's worth, I would not have tried to climb out at Vx. You have no hope of outclimbing a jet, It's not that far off -- I think (but am not certain) that a fully-loaded DC-9 has a best climb angle of around 650 ft/nm, while a small single-engine plane will manage something like 400-600 ft/nm at Vx depending on horsepower and load. Of course, the DC-9 has a much better climb *rate*, but that's not the concern here [...] I could be wrong, too, but I think even a loaded DC-9 can manage at least 1000-1500fpm... and might have to do so for noise abatement around the airport. I've heard that's why cloud clearances down around us VFR planes are 1000' above and 500' below. The extra space above is needed because an airliner is far more likely to be climbing out at high fpm... but descends at a slower rate for passenger comfort and ILS landings. Kev |
#5
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Kevin Darling wrote:
It's not that far off -- I think (but am not certain) that a fully-loaded DC-9 has a best climb angle of around 650 ft/nm, while a small single-engine plane will manage something like 400-600 ft/nm at Vx depending on horsepower and load. Of course, the DC-9 has a much better climb *rate*, but that's not the concern here [...] I could be wrong, too, but I think even a loaded DC-9 can manage at least 1000-1500fpm... and might have to do so for noise abatement around the airport. You need to know the forward speed as well. At 120 kt, 1500 fpm would be 750 ft/nm; at 180 kt, it would be only 500 ft/nm (but I think that the DC-9 can do better than that). In either case, the climb angle is not that much greater than that of a light single. All the best, David |
#6
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David Megginson wrote in message t.cable.rogers.com...
Kevin Darling wrote: It's not that far off -- I think (but am not certain) that a fully-loaded DC-9 has a best climb angle of around 650 ft/nm, while a small single-engine plane will manage something like 400-600 ft/nm at Vx depending on horsepower and load. Of course, the DC-9 has a much better climb *rate*, but that's not the concern here [...] I could be wrong, too, but I think even a loaded DC-9 can manage at least 1000-1500fpm... and might have to do so for noise abatement around the airport. You need to know the forward speed as well. At 120 kt, 1500 fpm would be 750 ft/nm; at 180 kt, it would be only 500 ft/nm (but I think that the DC-9 can do better than that). In either case, the climb angle is not that much greater than that of a light single. Yes, thanks. I goofed and posted just before I read that you were talking about ft/nm versus ft/min. And yep, the DC-9 can climb at up to 2900 fpm. Sorry 'bout the confusion. Best regards, Kevin |
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