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To reduce voltage drop from a charger, when a diode is inserted, the diode
should be a shottky type diode. If 3 amps maximum current is sufficient, a 1N5822 will work fine. Those diodes are available at Radio Shack. Voltage drop is about .3 volts. In many cases, a "protection" diode is not needed when charging a system. They simply prevent current from going the wrong direction when the charger is not connected. Solar panels may or may not require them. Many circuits show a diode in series with a solar charging panel. The theory is that it prevents current from reversing direction during darkness. In many cases, the diode is not necessary and the instruction books are guilty of simply copying a circuit without understanding it. The reason diodes are often not necessary in solar panel charging systems is that the panel itself is a diode. I always check with a ma meter, just to make sure. I installed a 100 ma (.1 amp) panel on a friend's motorglider (no electrical charging system or starter) and it has charged the battery for over a year with no problem. He is an occasional user and not a contester, nor does he fly many hours at a time. If you consider a 12 volt storage battery as being fully charged at about 14.2 volts and unusable for your purposes at 12 volts, you can consider the stored power available pretty much as a straight line with 14.2 as 100% and 12 as 0 %. That means that when the voltage is 13.1 volts, you have 50% power available. Batteries, both rechargeable and non-rechargeable may expect the voltage to go below 12 volts to achieve the rated amp hours, so if 12 is your minimum, you may need to de-rate your battery. The manufacturer should have a graph showing the actual capacity available with the maximum and minimum voltage you have in your electrical system. Colin |
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In many cases, a "protection" diode is not needed when charging a system.
They simply prevent current from going the wrong direction when the charger is not connected. Not connected to the AC power that is. When the charger is not connected to the battery, current would not flow because there is no completed circuit. Still early. Colin |
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