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#11
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Don Tuite wrote:
You get additional horsepower from going downhill, letting you maintain your speed. Telegraphic as ever, Ron. So, because I'm using the same throttle position as I was using in level flight, I'm descending while in a turn and banked at A degrees. The airplane seat is pushing on my butt at an angle A degrees from vertical. That can be resolved into a vertical vector and a horizontal vector aimed at the center of the circular path I'm describing. Meanwhile the back of the seat is exerting another force on my butt tangential to the circular path I'm describing in the horizontal, er, "plane." That force is a reaction to the thrust of the prop. If I "maintain my speed," I get the same lift I would have got from adding enough throttle so as not to lose altitude. That means the magnitude of the vertical component of the lift vector is still equal to mg and my rate of descent is constant. You were agreeing with me? (Never happened before.) Maintaining vertical equilbrium depends on maintaining the same speed as in straight and level flight, doesn't it? There's no force on you from the back of the seat, unless you're also getting a force from the wind in your face, say it's a powered hang glider. The additional thrust on the airplane from its spiraling downward into gravity is also a thrust on you yourself, so you don't feel it. If you keep the turn coordinated, you're pointing the nose slightly down the vertical to streamline into the downward spiral. The additional horsepower lets the wings run fast enough at their angle of attack to maintain the lift they need to hold the turn, where the engine alone does not suffice. -- Ron Hardin On the internet, nobody knows you're a jerk. |
#12
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Ron Hardin wrote:
Losing altitude at a constant rate (rather than accelerating downward) would be the same as maintaining a constant altitude, wouldn't it? (Vectors on a free-body diagram and all that) Don You get additional horsepower from going downhill, letting you maintain your speed. Power is a different issue than g-loading. Power has only coincidental impact on stall speed (you do get a small gain from the prop blast). |
#13
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Ron Natalie wrote:
Ron Hardin wrote: Losing altitude at a constant rate (rather than accelerating downward) would be the same as maintaining a constant altitude, wouldn't it? (Vectors on a free-body diagram and all that) Don You get additional horsepower from going downhill, letting you maintain your speed. Power is a different issue than g-loading. Power has only coincidental impact on stall speed (you do get a small gain from the prop blast). Power has a significant impact on airplane speed, however. -- Ron Hardin On the internet, nobody knows you're a jerk. |
#14
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Ron Hardin wrote:
Power is a different issue than g-loading. Power has only coincidental impact on stall speed (you do get a small gain from the prop blast). Power has a significant impact on airplane speed, however. and on whether you are climbing or descending. |
#15
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On Mon, 16 Oct 2006 23:22:40 GMT, Don Tuite
wrote: On Mon, 16 Oct 2006 22:41:58 GMT, Ron Hardin wrote: Don Tuite wrote: On 16 Oct 2006 13:28:37 -0700, "Snidely" wrote: Blanche Cohen wrote: Aircraft Turn Calculator www.csgnetwork.com/aircraftturninfocalc.html Interesting -- but doesn't speak to asltitude issues (loss of, or adjustments to avoid loss of). Losing altitude at a constant rate (rather than accelerating downward) would be the same as maintaining a constant altitude, wouldn't it? (Vectors on a free-body diagram and all that) Don You get additional horsepower from going downhill, letting you maintain your speed. Telegraphic as ever, Ron. So, because I'm using the same throttle position as I was using in level flight, I'm descending while in a turn and banked at A degrees. The airplane seat is pushing on my butt at an angle A degrees from vertical. That can be resolved into a vertical vector and a horizontal vector aimed at the center of the circular path I'm describing. Meanwhile the back of the seat is exerting another force on my butt tangential to the circular path I'm describing in the horizontal, er, "plane." That force is a reaction to the thrust of the prop. If I "maintain my speed," I get the same lift I would have got from adding enough throttle so as not to lose altitude. That means the magnitude of the vertical component of the lift vector is still equal to mg and my rate of descent is constant. You were agreeing with me? (Never happened before.) Maintaining vertical equilbrium depends on maintaining the same speed as in straight and level flight, doesn't it? Don I'll try this time: altitude = potential energy. Losing altitude means giving up potential energy. Where does that energy go? Into providing a greater (effective) angle of attack than you could at constant altitude and airspeed and thrust OR providing more airspeed than you could at constant altitude and AoA and thrust. Untelegraphic enough? Brian Whatcott Altus OK |
#16
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On Tue, 17 Oct 2006 16:56:26 GMT, Brian Whatcott
wrote: I'll try this time: altitude = potential energy. Losing altitude means giving up potential energy. Where does that energy go? Into providing a greater (effective) angle of attack than you could at constant altitude and airspeed and thrust OR providing more airspeed than you could at constant altitude and AoA and thrust. Untelegraphic enough? Yes. Energy conservation is always a good way to clarify things. Over the years, I've played Menos' slave boy to Ron's Socrates several times, but he usually requires that I show some effort before he moves out of ultar-terse mode. Don |
#17
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On Tue, 17 Oct 2006 18:32:42 GMT, Don Tuite
wrote: On Tue, 17 Oct 2006 16:56:26 GMT, Brian Whatcott wrote: I'll try this time: altitude = potential energy. Losing altitude means giving up potential energy. Where does that energy go? Into providing a greater (effective) angle of attack than you could at constant altitude and airspeed and thrust OR providing more airspeed than you could at constant altitude and AoA and thrust. Untelegraphic enough? Yes. Energy conservation is always a good way to clarify things. Over the years, I've played Menos' slave boy to Ron's Socrates several times, but he usually requires that I show some effort before he moves out of ultar-terse mode. Don Good attitude, Don! :-) Brian Whatcott Altus OK |
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