![]() |
If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
#71
|
|||
|
|||
![]() "Le Chaud Lapin" wrote in message ... On Jun 9, 10:48 pm, "Robert M. Gary" wrote: On Jun 9, 8:18 pm, Le Chaud Lapin wrote: Both these explanations are true, but one of them eliminates the need for $30 product (or $30,000 aircraft) to know what is going on. I find that its pretty difficult to teach students to fly without the aircraft. That brings us full-circle to a theme that was mildly explored in another post - what utility, if any, is there in using a simulator to learn things that do not require actual flying. So here the question would be whether it is possible to understand how a trim tab works without ever having flown an aircraft. I have flown in DA-20 and Tomahawk, but I do not think actual flight would have been necessary to understand how trim tab works. -Le Chaud Lapin- Well, it's been a long time since I flew a Tomahawk and I never flew the DA-20, and my Tomahawk manual has gone AWOL; but I don't recall the Tomahawk having a tab--IIRC, it had a spring system. That gives a different "feel" and a different contribution to the feel of the primary controls; but there should have been little motivation for MS to attempt to model those subtleties--especially since the purchaser has choices in the physical controls (yokes, etc.) attached to his computer. Knowing how the systems work can be intellectually interesting for the technically oriented; essential for designers, builders and mechanics; and can easily save your life in the event of a systems failure in a real aircraft. Therefore, most members of this group need to know the systems on the aircraft they actually fly; but have no need for all of the possible combinations and permutations. The bottom line is that you are apparently part of the primary market for MSFS and it gives you enjoyment. OTOH, most members of this group (who use it at all) use it as a tool for procedure training, such as practicing intercepts and approaches, and do so for efficiency rather than entertainment. Peter |
#72
|
|||
|
|||
![]()
On Jun 10, 9:32*am, "Peter Dohm" wrote:
Well, it's been a long time since I flew a Tomahawk and I never flew the DA-20, and my Tomahawk manual has gone AWOL; but I don't recall the Tomahawk having a tab--IIRC, it had a spring system. *That gives a different "feel" and a different contribution to the feel of the primary controls; but there should have been little motivation for MS to attempt to model those subtleties--especially since the purchaser has choices in the physical controls (yokes, etc.) attached to his computer. Knowing how the systems work can be intellectually interesting for the technically oriented; essential for designers, builders and mechanics; and can easily save your life in the event of a systems failure in a real aircraft. *Therefore, most members of this group need to know the systems on the aircraft they actually fly; but have no need for all of the possible combinations and permutations. My OP did not mention anything about combinations and permutations. It was asked in general, and then just for C172, as an example. The bottom line is that you are apparently part of the primary market for MSFS and it gives you enjoyment. *OTOH, most members of this group (who use it at all) use it as a tool for procedure training, such as practicing intercepts and approaches, and do so for efficiency rather than entertainment. Yes, I do enjoy understanding things, but my primary motivation is efficiency of savings. It was a lot cheaper to check my understanding of how trim tab works using a simulator than it was to drive 40km out to airport and fiddle with a real plane. -Le Chaud Lapin- |
#73
|
|||
|
|||
![]()
"BDS" wrote in message
... Some students want the first approach, some may want the second - it's probably 95% to 5%. If you assume they all want the more detailed explanation for everything, you will have frustrated students who either think that flying is too complicated for them to learn, or who quit because they are bored. When I took driver's ed in high school they didn't explain the inner workings of a carburetor, nor did they need to in order for me to be able to learn how to drive. Knowing how a carburetor works and having the ability to tear one down and put it back together again does not make me a better driver. You want to know every detail - fine. You just need to find an instructor who is willing and able to do that for you. As you know, not all of them are nor do they need to be in order to be able to teach you to fly and fly well. I suspect you dispute that fact, but history has already proven you wrong. In general, I agree with you--one certainly didn't need to know the inner workings of the carburetor. However, it could be very usefull to understand what the throttle (accelerator) return spring did! That sort of information is in the POH for any aircraft certified under Part 23. OTOH, the answers to the original question posted by the OP might be included over the course of an airframe mechanic's curriculum--or might not. Peter |
#74
|
|||
|
|||
![]()
One point about the lift fairy sitting on the tail I'd like to
understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. . On Jun 8, 5:18 am, WingFlaps wrote: On Jun 8, 5:08 pm, Le Chaud Lapin wrote: Hi All, This post is primarily directed toward student pilots like myself. First, I am not asking because I want to know the answer (I already know), but do a little experiment. I have maybe 7 or 8 different sources of flight information that I rely on for ground school (Jeppesen, FAA Handbooks, etc), and none of them said _how_ it worked in sufficient detail, they only said what one must do to make the plane pitch up or downard. So for you students, please do not cheat and do what I did, which is watch the airfoils move as you move the trim control. Also, it would help if you did not think about the correct answer too much, which would lead you to the correct answer, thereby defeating the purpose of my experiment. So, without cheating, and without asking an experienced pilot or mechanic,... What exactly happens when the trim is adjusted to point the nose upward? Well, since you frame it as a troll: You scare the lift faries to run forward by waving a very nasty bit of metal at them. YAWN Cheers |
#75
|
|||
|
|||
![]()
Tina wrote:
One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi |
#76
|
|||
|
|||
![]()
On Jun 10, 1:09 pm, Tauno Voipio wrote:
Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? be |
#77
|
|||
|
|||
![]()
Tina wrote:
On Jun 10, 1:09 pm, Tauno Voipio wrote: Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? Yes - they do bring back some, and this is the reasoning behind e.g. Rutan's Voyager, The price is that the canard (front wing) has to stall first unless you want to fall to ground in reverse when the thing stalls. The rumours are that the canards are a PITA to land nicely. -- -Tauno |
#78
|
|||
|
|||
![]()
Thanks again. My intelligent but ignorant guess is designing canards
so that they stall first should not take a genius, but there may be traps I don't see. The world is safe, though, since I don't design airplane. The landing issue you raised is pretty neat, since most of us -- especially Mooney drivers -- are careful about airspeed on final and in the flare, and like to land with the wings almost stalled. But in the case of a canard if that stalls first I think the airplane would very enthusiastically want to pitch forward hard enough to bend the nosewheel! At least with the stabilizer still flying the nose might be able to be put down more gently. You've provided some nice insights, thanks. On Jun 10, 2:14 pm, Tauno Voipio wrote: Tina wrote: On Jun 10, 1:09 pm, Tauno Voipio wrote: Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since theI center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? Yes - they do bring back some, and this is the reasoning behind e.g. Rutan's Voyager, The price is that the canard (front wing) has to stall first unless you want to fall to ground in reverse when the thing stalls. The rumours are that the canards are a PITA to land nicely. -- -Tauno |
#79
|
|||
|
|||
![]()
On Jun 11, 4:00*am, Nomen Nescio wrote:
-----BEGIN PGP SIGNED MESSAGE----- From: Tina I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. I prefer ergs/minute. Small units to make a couch potato feel happy? Cheers |
#80
|
|||
|
|||
![]()
On Tue, 10 Jun 2008 11:24:39 -0700 (PDT), Tina
wrote: Thanks again. My intelligent but ignorant guess is designing canards so that they stall first should not take a genius, but there may be traps I don't see. The world is safe, though, since I don't design airplane. The landing issue you raised is pretty neat, since most of us -- especially Mooney drivers -- are careful about airspeed on final and in the flare, and like to land with the wings almost stalled. But in the case of a canard if that stalls first I think the airplane would very enthusiastically want to pitch forward hard enough to bend the nosewheel! I haven't flown a canard, but my son has done a lot of flying in one that was under development. You are right... you don't want to stall the canard on landing. You fly it all the way to the ground. Three problems with the canard, as my son saw it, was lack of forward visibility on landing, drag from the canard in cruise flight (a fixed canard has to have its AOA greater than the wing and enough surface to generate lift) and ice shedding off the wings through the propelllor. Piaggio solved the drag problem, partially, with a three surface aircraft and a relatively small canard. I believe Beechcraft attempted to solve it with a variable sweep canard, but I could be wrong. At least with the stabilizer still flying the nose might be able to be put down more gently. You've provided some nice insights, thanks. My son says canard landings are like the "Little girl with the curl in the middle of her forehead"... when they are good, they are very very good, but when they are bad they are horrid. :-) Ron Kelley |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
F-100 detail | Pjmac35 | Aviation Photos | 0 | July 26th 07 10:29 AM |
Finding "Neutral" Position on Piper Elevator/Trim Tab | [email protected] | Owning | 10 | December 7th 06 01:43 PM |
Detail pops in too late in FS2004 | CatharticF1 | Simulators | 0 | August 27th 03 03:25 AM |