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![]() "Tman" wrote in message ... Somebody posed that seemingly simple question to me, but kept coming back to the point that they stumped me.... And I am stumped. What do you see wrong with the logic in this dialog? Q: Why do I need to lean out my carb when I climb? I'll take a stab at this one. Its a very good question. A Stromberg carb does not require a mixture adjustment (at least below 8000'). It diverts low pressure air from the back of the venturi into the fuel float bowl. In this way it is "self regulating" just as you describe. The amount of fuel drawn in is proportional to the air pressure. Older classic airplanes will use this type of carberator system and thus have no mixture. I believe more "conventional" systems use a mixture simply becuase the logistics of balancing all the jets is difficult and because slight misadjustments in the orifice that tunes the ratio might result in a catastrophically lean mixture. A carburetor can have four jet circuits for idle, midrange, main and accelerator (I am quoting more Rochester Quadrajet than Lycoming -- so aircraft mechanics please jump in). Your mixture valve is in front of all of these and so restricts the fuel thru all of them. If you have a higher performance engine, or operate at a higher range of altitudes, I suspect you cannot build a mechanical metering system that covers the range without regions of overly rich or overly lean so we have the man in the loop. I am pretty sure of my answer but I'd invite any clarification. Todd |
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On Jan 19, 7:05 pm, "Todd W. Deckard" wrote:
"Tman" wrote in message Q: Why do I need to lean out my carb when I climb? I'll take a stab at this one. Its a very good question. A Stromberg carb does not require a mixture adjustment (at least below 8000'). It diverts low pressure air from the back of the venturi into the fuel float bowl. In this way it is "self regulating" just as you describe. The amount of fuel drawn in is proportional to the air pressure. Older classic airplanes will use this type of carberator system and thus have no mixture. The Stromberg carb's bowl is vented to a dead airspace behind the venturi just like all the other carbs and has the same rich problem with altitude that the others do. The Stromberg was built with a mixture control valve cavity in the upper casting and many were left empty and capped off to run full rich, or had the valve installed and the lever wired to the full rich position. Most of the population, at least years ago, lived near the coasts and flew puddlejumpers that didn't fly very high. Fuel was cheap, too. So the makers didn't see another control as having much value, expecially the back-suction mixture type that the Stromberg uses and which will not act as an idle cutoff for shutdown. I have one of those old carbs on my airplane. I operate off a strip that's around 3000' ASL. I machined the necessary parts for the mixture control, they being very rare now, and installed them. It works fine. It's a homebuilt and so such doings are permitted. Air from behind the venturi where the air, being still, is at or near ambient pressure, and this air passes into the cavity I mentioned. There's a much smaller port in the cavity that leads to the venturi itself and has considerably less pressure when the throttle is open. Air is sucked out here. A third port into the cavity leads to the bowl itelf. As long as the port from behind the venturi is wide open, air can come in from behind the venturi and get sucked into the venturi proper without exerting any negative pressure on the bowl. When we lean, the mixture control simply starts choking off the air supply from behind the venturi and allows the lower venturi pressure to lower the bowl pressure, which reduces fuel flow through the jet into the nozzle. Because the venturi's pressure drop is about zero when at idle, it won't suck back on the bowl to act as an idle cutoff at shutdown. I believe more "conventional" systems use a mixture simply becuase the logistics of balancing all the jets is difficult and because slight misadjustments in the orifice that tunes the ratio might result in a catastrophically lean mixture. A carburetor can have four jet circuits for idle, midrange, main and accelerator (I am quoting more Rochester Quadrajet than Lycoming -- so aircraft mechanics please jump in). The typical light-aircraft carb like the Marvel Schebler/ Precision Aeromotive/Tempest carb has one jet. The mixture control is in the bottom of the float bowl and is a small valve that varies fuel flow directly, from max to nothing at all. Your mixture valve is in front of all of these and so restricts the fuel thru all of them. If you have a higher performance engine, or operate at a higher range of altitudes, I suspect you cannot build a mechanical metering system that covers the range without regions of overly rich or overly lean so we have the man in the loop. Yup, you can, and it's done, too. It's just not cheap or simple. There are various aneroid actuators that adjust fuel flow for altitude, along with power valves that increase fuel flow for takeoff and climb and other overriding devioces that prevent overly lean conditions. Some pressure carbs (no float bowl) have these systems and are similar in some ways to the fuel controllers used on fuel injection systems. These types measure ambient air pressure, air velocity through the carb, fuel supply pressure and fuel delivery pressure and so forth and make the adjustments constantly. This is diagram of a pressure carb, without the aneroid mixture control. I can't find one on the 'net with it: http://www.navioneer.org/riprelay/Th...bFlowChart.jpg Dan |
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![]() "Bertie the Bunyip" wrote in message ... Tman wrote in news:- : wrote: On Jan 19, 7:05 pm, "Todd W. Deckard" wrote: It diverts low pressure air from the back of the venturi into the fuel float bowl. Never taken a close look at an airplane carb, but I understand that the standard config (not this stromberg, but rather something like in a basic 172N) has a fuel-bowl vent upstream of the venturi, making the air pressure in the fuel bowl pretty much equal to the air intake pressure.... Kind of like a standard auto carb from a few years ago when they still had them. Let me know if that's not right. They're basically a float bowl and a tube. not a lot to complicate them, really. Probably the simplest carbs in operation today. Bertie You're an idiot. |
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"Maxwell" #$$9#@%%%.^^^ wrote in :
"Bertie the Bunyip" wrote in message ... Tman wrote in news:- : wrote: On Jan 19, 7:05 pm, "Todd W. Deckard" wrote: It diverts low pressure air from the back of the venturi into the fuel float bowl. Never taken a close look at an airplane carb, but I understand that the standard config (not this stromberg, but rather something like in a basic 172N) has a fuel-bowl vent upstream of the venturi, making the air pressure in the fuel bowl pretty much equal to the air intake pressure.... Kind of like a standard auto carb from a few years ago when they still had them. Let me know if that's not right. They're basically a float bowl and a tube. not a lot to complicate them, really. Probably the simplest carbs in operation today. Bertie You're an idiot. Nope. But please don't let that stop you maxie. Bertie |
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Bertie the Bunyip wrote:
"Maxwell" #$$9#@%%%.^^^ wrote in : "Bertie the Bunyip" wrote in message ... Tman wrote in news:- : wrote: On Jan 19, 7:05 pm, "Todd W. Deckard" wrote: It diverts low pressure air from the back of the venturi into the fuel float bowl. Never taken a close look at an airplane carb, but I understand that the standard config (not this stromberg, but rather something like in a basic 172N) has a fuel-bowl vent upstream of the venturi, making the air pressure in the fuel bowl pretty much equal to the air intake pressure.... Kind of like a standard auto carb from a few years ago when they still had them. Let me know if that's not right. They're basically a float bowl and a tube. not a lot to complicate them, really. Probably the simplest carbs in operation today. Bertie You're an idiot. Nope. But please don't let that stop you maxie. What's new on teh gasket-front, Cap'N? -- ah |
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Tman,
I've been pondering your question quite a bit. I believe I have it. In deference to Dan my Camaro never idled correctly. Ultimately your engine depends on the mass flow of air divided by the mass flow of fuel. But the amount of fuel drawn up is a function of the pressure difference in the carbureture venturi. So here goes: The carb throat is a double venturi and a manometer between the opening and the neck would show a theoretical pressure drop of: p(opening) - p(neck) = .5 * density of air * { velocity(neck)^2 - velocity(opening)^2 } (Lets ignore carb ice for a second and say that the air is incompressible). Bernoulli got the idea from Newton thats why the 1/2 m v squared. Now discouragingly this has the density in front of it, which is why you posed the question. The difference in pressures is directly proportional to the density. Now the low pressure in the neck of the venturi is what is drawing the fuel up (or properly the difference between the neck and ambient). Again we use Bernoulli to describe the forces acting on a particle moving along a streamline -- and this time it is properly incompressible. { Pressure / density } + .5 * { velocity ^ 2 } + gravity * change_in_height = a constant Again, Bernoulli copped it all from Newton and was just telling us that kinetic energy + potential energy = a constant. If we apply this to your fuel being drawn up we get: (#) p (ambient) - p (neck) / density of fuel = .5 * (velocity of fuel) ^2 + (gravity * vertical distance from bowl to jet) However mass flow is the density * the size of the pipe * the velocity. So the mass flow of air = density of air * carb barrel size * velocity (opening) But from (#) the mass flow of fuel is being determined by the pressure difference (which also carries the air density) so Air over Fuel cancels your density term. An altitude compensating carburator puts a small vacuum on the fuel to prevent the rho from dividing out. Mr Wizard could have explained this better that as the air gets thinner it sucks on the straw with less force but it takes less force to slurp up the gas becuase of the reduced pressure. So the gas drawn up stays about the same, however the mass flow of air drops off with density so the mixture richens. Q.E.D. Good question. If I ever become a physics teacher I am going to put this one on the final! |
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I think you are making this waaaay to complicated. The volume of air going
through the venturi remains the same as you climb but the amount of oxygen (the component needed to burn the fuel) decreases. The volume of air remains the same so the fuel drawn out of the float bowl remains the same. There is less oxygen so the mixture become rich. That's my story and I am sticking to it. -- *H. Allen Smith* WACO - We are all here, because we are not all there. "Todd W. Deckard" wrote in message ... Tman, I've been pondering your question quite a bit. I believe I have it. In deference to Dan my Camaro never idled correctly. Ultimately your engine depends on the mass flow of air divided by the mass flow of fuel. But the amount of fuel drawn up is a function of the pressure difference in the carbureture venturi. So here goes: The carb throat is a double venturi and a manometer between the opening and the neck would show a theoretical pressure drop of: p(opening) - p(neck) = .5 * density of air * { velocity(neck)^2 - velocity(opening)^2 } (Lets ignore carb ice for a second and say that the air is incompressible). Bernoulli got the idea from Newton thats why the 1/2 m v squared. Now discouragingly this has the density in front of it, which is why you posed the question. The difference in pressures is directly proportional to the density. Now the low pressure in the neck of the venturi is what is drawing the fuel up (or properly the difference between the neck and ambient). Again we use Bernoulli to describe the forces acting on a particle moving along a streamline -- and this time it is properly incompressible. { Pressure / density } + .5 * { velocity ^ 2 } + gravity * change_in_height = a constant Again, Bernoulli copped it all from Newton and was just telling us that kinetic energy + potential energy = a constant. If we apply this to your fuel being drawn up we get: (#) p (ambient) - p (neck) / density of fuel = .5 * (velocity of fuel) ^2 + (gravity * vertical distance from bowl to jet) However mass flow is the density * the size of the pipe * the velocity. So the mass flow of air = density of air * carb barrel size * velocity (opening) But from (#) the mass flow of fuel is being determined by the pressure difference (which also carries the air density) so Air over Fuel cancels your density term. An altitude compensating carburator puts a small vacuum on the fuel to prevent the rho from dividing out. Mr Wizard could have explained this better that as the air gets thinner it sucks on the straw with less force but it takes less force to slurp up the gas becuase of the reduced pressure. So the gas drawn up stays about the same, however the mass flow of air drops off with density so the mixture richens. Q.E.D. Good question. If I ever become a physics teacher I am going to put this one on the final! |
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On Jan 21, 7:19 am, "Allen" wrote:
I think you are making this waaaay to complicated. The volume of air going through the venturi remains the same as you climb but the amount of oxygen (the component needed to burn the fuel) decreases. The volume of air remains the same so the fuel drawn out of the float bowl remains the same. There is less oxygen so the mixture become rich. More properly, the weight of the air decreases. Oxygen still makes up 21% of the air. Dan |
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