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Zero G profile



 
 
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  #1  
Old May 8th 07, 10:47 AM posted to rec.aviation.piloting
mike regish
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Posts: 438
Default Zero G profile

What's the best way to fly a zero G parabola? My kids are hooked on them and
they're actually learning some science from it. I'd like to get a little
more duration without getting too fast.

I usually do a little climb until the speed bleeds off some and then push
over firmly. Should I pull the power over the top as I'm pushing?

mike


  #2  
Old May 8th 07, 01:58 PM posted to rec.aviation.piloting
Paul Tomblin
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Posts: 690
Default Zero G profile

In a previous article, "mike regish" said:
What's the best way to fly a zero G parabola? My kids are hooked on them and
they're actually learning some science from it. I'd like to get a little
more duration without getting too fast.

I usually do a little climb until the speed bleeds off some and then push
over firmly. Should I pull the power over the top as I'm pushing?


Why don't you get up to full speed, pitch up, then push down a bit? That
way you can get negative G's on the way up while you're bleeding off the
speed.

--
Paul Tomblin http://blog.xcski.com/
I mean, if went 'round saying I was a perl hacker, just because some
moistened bint lobbed a "Perl for Dummies" at me, they'd put me away!
-- Randy the Random
  #3  
Old May 8th 07, 02:43 PM posted to rec.aviation.piloting
Dale
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Posts: 31
Default Zero G profile

In article ,
"mike regish" wrote:

What's the best way to fly a zero G parabola? My kids are hooked on them and
they're actually learning some science from it. I'd like to get a little
more duration without getting too fast.

I usually do a little climb until the speed bleeds off some and then push
over firmly. Should I pull the power over the top as I'm pushing?

mike


While your doing the zero G take a glance at the oil pressure
gauge...you may find it has dropped very low. FYI
  #4  
Old May 8th 07, 08:23 PM posted to rec.aviation.piloting
JGalban via AviationKB.com
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Posts: 356
Default Zero G profile

mike regish wrote:

I usually do a little climb until the speed bleeds off some and then push
over firmly. Should I pull the power over the top as I'm pushing?


That's what I do. Keeps me from accelerating excessively in the dive.

John Galban=====N4BQ (PA28-180)

--
Message posted via AviationKB.com
http://www.aviationkb.com/Uwe/Forums...ation/200705/1

  #5  
Old May 19th 07, 02:28 PM posted to rec.aviation.piloting
Mxsmanic
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Posts: 9,169
Default Zero G profile

JGalban via AviationKB.com writes:

That's what I do. Keeps me from accelerating excessively in the dive.


Your acceleration is fixed in a parabola. It is always exactly -1.0 G, which
precisely negates the pull of gravity and gives you the zero gravity
objective.

--
Transpose mxsmanic and gmail to reach me by e-mail.
  #6  
Old May 19th 07, 03:09 PM posted to rec.aviation.piloting
Maxwell
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Posts: 1,116
Default Zero G profile


"Mxsmanic" wrote in message
...
JGalban via AviationKB.com writes:

That's what I do. Keeps me from accelerating excessively in the dive.


Your acceleration is fixed in a parabola. It is always exactly -1.0 G,
which
precisely negates the pull of gravity and gives you the zero gravity
objective.


Clueless as usual.


  #7  
Old May 19th 07, 04:42 PM posted to rec.aviation.piloting
Mxsmanic
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Posts: 9,169
Default Zero G profile

Maxwell writes:

Clueless as usual.


A zero-G parabola is a ballistic trajectory; it always involves acceleration
towards the ground (in the direction of gravity) at exactly 1.0 G. That's how
it produces the "zero-G" effect.

This being so, you cannot change the acceleration of the aircraft along the
vertical axis without losing the zero-G effect.

Essentially, if you fire a cannonball next to the aircraft, your aircraft
needs to follow the same path as the cannonball in order to become
"weightless."

--
Transpose mxsmanic and gmail to reach me by e-mail.
  #8  
Old May 19th 07, 05:29 PM posted to rec.aviation.piloting
Maxwell
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Posts: 1,116
Default Zero G profile


"Mxsmanic" wrote in message
...

A zero-G parabola is a ballistic trajectory; it always involves
acceleration
towards the ground (in the direction of gravity) at exactly 1.0 G. That's
how
it produces the "zero-G" effect.

This being so, you cannot change the acceleration of the aircraft along
the
vertical axis without losing the zero-G effect.

Essentially, if you fire a cannonball next to the aircraft, your aircraft
needs to follow the same path as the cannonball in order to become
"weightless."


Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.


  #9  
Old May 20th 07, 01:05 AM posted to rec.aviation.piloting
Bertie the Bunyip[_2_]
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Posts: 896
Default Zero G profile

Mxsmanic wrote in
:

Maxwell writes:

Clueless as usual.


A zero-G parabola is a ballistic trajectory;


No, it isn't.


bertie
  #10  
Old May 19th 07, 08:45 PM posted to rec.aviation.piloting
mike regish
external usenet poster
 
Posts: 438
Default Zero G profile

Uhh..hate to burst your bubble again, but -1 g would have you straining at
your seatbelt with a force of 1 g. If you're not wearing one, you would be
exerting 1 g against the roof.

mike

"Mxsmanic" wrote in message
...
JGalban via AviationKB.com writes:

That's what I do. Keeps me from accelerating excessively in the dive.


Your acceleration is fixed in a parabola. It is always exactly -1.0 G,
which
precisely negates the pull of gravity and gives you the zero gravity
objective.

--
Transpose mxsmanic and gmail to reach me by e-mail.



 




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