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#1
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A given glider is at level flight, IAS= 100 knots.After a pull-up, will it
achieve more height gain with 100 liters (100 kgs) of ballast than with empty ballast???? Réjean |
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#2
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The difference in height will be negligible.
The glider's energy, both potential & kinetic is proportional to Mass so the height gain for a given loss of velocity will be the same. However the ballasted glider will have a better sink rate at 100kts than the unballasted one so during the few seconds of the pull-up it will 'lose' less height. On the other side of the equation the un-ballasted glider will be able to pull up to a lower speed, so it's change in velocity will be greater so the resulting height gain may be more. (My money - if I had any - would be on the un-ballasted one) |
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#3
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Kevin Neave k wrote in message ...
The difference in height will be negligible. Not true. A full load of water makes a HUGE difference in pullup altitude gained The glider's energy, both potential & kinetic is proportional to Mass so the height gain for a given loss of velocity will be the same. Again, wrong - check your basic physics. You even say that the energy is proportional to mass. Therefore, more mass, more energy, more altitude gained. You appear to be confusing velocity with mass. However the ballasted glider will have a better sink rate at 100kts than the unballasted one so during the few seconds of the pull-up it will 'lose' less height. True, but the crossover point is quickly reached so this effect is probably negligable. On the other side of the equation the un-ballasted glider will be able to pull up to a lower speed, so it's change in velocity will be greater so the resulting height gain may be more. If you pull up below the ballasted sink rate crossover speed, sure a heavy glider will gain less. But at those speeds neither glider will gain much anyway. The real test is what you can gain at redline. (My money - if I had any - would be on the un-ballasted one) Too bad, I love a sure thing! Kirk Stant LS6-b (which loves ballasted pullups!) |
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#4
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#5
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#6
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Tim Olson wrote:
Total energy = kinetic energy + potential energy kinetic energy = 1/2 mass * velocity squared potential energy = mass * gravitational constant * height total energy (altitude 1) = total energy (altitude 2) [conservation of energy] Since mass is a constant factor on both sides of the equation, it cancels out. Therefore there should theoretically be negligible difference in the pullup altitude gained between the ballasted and unballasted cases. -- Tim Olson Adding energy lost due to drag into the soup: m = mass v1 = initial speed h1 = initial altitude v2 = final speed h2 = final altitude total energy(alt 1) = total energy (alt 2) + energy lost due to drag 1/2*m*v1^2 + m*g*h1 = 1/2*m*v2^2 + m*g*h2 + Ed dividing both sides by m: 1/2*v1^2 + g*h1 = 1/2*v2^2 + g*h2 + Ed/m Now compare two gliders, starting with same speed, same altitude, level flight. Both pull up and level out with same final speed (just to keep things even). The above holds for both gliders, so: (1) 1/2*v1^2 + g*h1 = 1/2*v2^2 + g*h21 + Ed/m1 (2) 1/2*v1^2 + g*h1 = 1/2*v2^2 + g*h22 + Ed/m2 substracting (1)-(2): 0=g(h21 - h22) + Ed(1/m1 - 1/m2) where h21 is final altitude for glider 1 and h22 for glider 2 and masses m1 for glider 1 and m2 for glider 2. We get: h22-h21 = Ed/g(1/m1 - 1/m2) So if m2 m1, h22 h21. The heavier glider will get more altitude. But not very much... Approximating Ed from sink rate (energy lost is m*g*(sink rate)*time) the altitude difference for masses 360kg and 460kg is a bit over one meter. But then again, to be exact, Ed is bigger for the heavier glider (same speed, more mass, need bigger AOA - more drag). Please point out any mistakes (well since it's the Usenet, I'm sure you will ![]() Jere jere at iki.fi |
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#7
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I think Kevin's right. (at least to the first order).
In a pullup you trade kinetic energy for potential energy, so (neglecting friction effects) the physics are (mV^2)/2=mgh -- kinetic equals potential energy. Or (solving for h): h=(V^2)/2g (the mass cancels out). You can try to add the drag parts back in, but the time is so short, I don't think it will not add up to much. I think maybe ther reason people associate ballast with taller zoomies is because the cruise speeds with ballast are higher. For my ship a McCready 10 pullup yields 700 feet with full ballast, 530 feet dry, but the speed is 15 knots higher. At 21:00 08 September 2003, Kirk Stant wrote: Kevin Neave wrote in message news:... The difference in height will be negligible. Not true. A full load of water makes a HUGE difference in pullup altitude gained The glider's energy, both potential & kinetic is proportional to Mass so the height gain for a given loss of velocity will be the same. Again, wrong - check your basic physics. You even say that the energy is proportional to mass. Therefore, more mass, more energy, more altitude gained. You appear to be confusing velocity with mass. However the ballasted glider will have a better sink rate at 100kts than the unballasted one so during the few seconds of the pull-up it will 'lose' less height. True, but the crossover point is quickly reached so this effect is probably negligable. On the other side of the equation the un-ballasted glider will be able to pull up to a lower speed, so it's change in velocity will be greater so the resulting height gain may be more. If you pull up below the ballasted sink rate crossover speed, sure a heavy glider will gain less. But at those speeds neither glider will gain much anyway. The real test is what you can gain at redline. (My money - if I had any - would be on the un-ballasted one) Too bad, I love a sure thing! Kirk Stant LS6-b (which loves ballasted pullups!) |
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#8
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One trivial point for Jere's post is that the stalling
speed for the unballasted glider will be lower, so this guy can pull up to a slower speed & therefore regain more altitude. Anyone out there want to know why there's a discrepancy between the maths (which say that there's not gonna be a measurable difference between the two) and 'popular' experience which says that the heavy glider wins? At 17:12 09 September 2003, Jere Knuuttila wrote: Adding energy lost due to drag into the soup: m = mass v1 = initial speed h1 = initial altitude v2 = final speed h2 = final altitude total energy(alt 1) = total energy (alt 2) + energy lost due to drag 1/2*m*v1^2 + m*g*h1 = 1/2*m*v2^2 + m*g*h2 + Ed dividing both sides by m: 1/2*v1^2 + g*h1 = 1/2*v2^2 + g*h2 + Ed/m Now compare two gliders, starting with same speed, same altitude, level flight. Both pull up and level out with same final speed (just to keep things even). the altitude difference for masses 360kg and 460kg is a bit over one meter. But then again, to be exact, Ed is bigger for the heavier glider (same speed, more mass, need bigger AOA - more drag). Please point out any mistakes (well since it's the Usenet, I'm sure you will ![]() Jere jere at iki.fi |
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#9
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Anyone out there want to know why there's a discrepancy
between the maths (which say that there's not gonna be a measurable difference between the two) and 'popular' experience which says that the heavy glider wins? I dunno. According to my math, the heavier one does win. Also, according to my experience, the heavier one does win. Jim Vincent CFIG N483SZ |
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#10
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On 9 Sep 2003 17:44:24 GMT, Kevin Neave
k wrote: One trivial point for Jere's post is that the stalling speed for the unballasted glider will be lower, so this guy can pull up to a slower speed & therefore regain more altitude. Anyone out there want to know why there's a discrepancy between the maths (which say that there's not gonna be a measurable difference between the two) and 'popular' experience which says that the heavy glider wins? Could this be due to speed difference at cruise or fast cruise speeds? One point that hasn't been considered by those arguing that the ballasted glider is faster forget that this is NOT the case at Vne, which doesn't change with glider weight. -- martin@ : Martin Gregorie gregorie : Harlow, UK demon : co : Zappa fan & glider pilot uk : |
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