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This brings to mind a clever circumvention of the FCC regulations on Family
Radio Service (FRS)tranceivers. The rules say that a FRS transmitter and antenna must be integrated - i.e. handhelds are OK but not roof antennas. Radio Shack brought out a transceiver/antenna unit with a very long mike cord and all transceiver controls in the mike which meant that the antenna/transceiver with a magnetic base could be on the roof of a car. It met the rules and worked really well but the FCC frowned on the effort and it was withdrawn from the market. So, why not extend the idea to built-in units? Put a small tranceiver unit in the antenna base and a separate control head in the panel. This eliminates all the RF coax problems. Not without problems of course. I'm sure it't more important in the GHz bands than in the 2-meter bands. Mounting a tranceiver in the fin with the antenna creates access and W&B issues but it looks solvable. Bill Daniels "Ralph Jones" wrote in message ... On 31 Jan 2007 08:00:31 -0800, "ContestID67" wrote: I have a question for this august body. I found a link on the 1-26 associations web site talking about the proper length of an antenna for operation at 123.3Mhz. This turns out to be; 1/4 wave Length: 0.61 m or 23.95 in 3/4 wave Length: 1.82 m or 71.84 in I was curious about the length of the coax. I was under the impression that to get the maximum power out of the antenna, that the combined total length of the coax *AND* the antenna needs to be taken into consideration and needs to be an even number of wavelengths. That prevents power from reflecting at the tip of the antenna and then back into the trasceiver. This can not only rob radiated power but might also damage the transceiver. A VSWR meter is used to tune this for maximum radiated power typically by adjusting the length of the antenna. I may be all wet on this subject as I am an electronics engineer (a bit pusher) and not an RF electrical engineer. Any comments? If the transmitter output circuit, the coax and the antenna all have the same characteristic impedance, no reflections occur; the VSWR is 1; radiated power is maximized; and the length of the coax is essentially immaterial. If there is an impedance mismatch anywhere in the system, there will be reflections and the VSWR will be more than 1. This will affect the signal at least two ways: (1) The impedance the coax presents to the transmitter will be something other than its characteristic impedance, creating an impedance mismatch at the output circuit. That will reduce the amount of power transferred into the system to begin with, as well as possibly overloading the output circuit. The amount of this impedance mismatch will depend on the length of the coax. The math gets interesting he as an extreme example, a 1/4 wavelength line shorted at one end looks like an open circuit from the other, and if open at one end it looks like a short from the other! (2) Every time a wave hits one end of the coax, some part of it gets transferred and some gets reflected back to the other end, where the same happens again. Some of the energy goes into the antenna the first time, and some of it makes multiple trips. If the coax were made of perfect conductors with perfect insulators, this back-and-forth travel would be immaterial and all the power that gets into the line (after being reduced by the impedance mismatch at the transmitter) would eventually get radiated by the antenna. But they don't sell perfect conductors and insulators at Radio Shack, so every foot of coax represents measurable resistive losses. rj |
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